Recent content by phyznut

Hi all, I'm in need of some advice urgently. Let me give a little background about myself. I"m currently an undergrad in engineering at a US college. I'm currently a senior and I'm scheduled to graduate at the end of Fall 08' semester. I am doing great in school with A's in most of my...

Can no one help. Would I have to use the voltage divider? How do i use it?

Ok then so with R2 removed, the circuit is now series. That makes the current the same for the remaining resistors. So if I_2 is 0, then the voltage between that point is also zero? That doesn't seem right though. I still don't get it, please give me another hint.

I'm trying to find the current and voltage across R2 using thenenin. http://img209.imageshack.us/img209/4606/thv15ph.png I've managed to find Rth, which is equal to (R1 + R4)||(R3 + R5). That comes out to about 2.9 ohms. I need help with finding the Vth (Vab) though...

Thanks for all your help mezarashi :smile:

Here is how I would analyze it. Since R4 would have a different resistance, be it higer or lower than that of R2. They must obviously be in parallel because both of them would have different amounts of current through them. If R4 = R2, then they would have the same current. But the current...

I think I'm beginning to understand a little now. DId I illustrate it correctly. If we call the point to the right of R1 A, and the bottom of R2 B. The top of R2 C. The current could flow from C through A to B. It could also go from C directly to B right...

Well it must first go across resistors 1 and 3 before reaching its destination. But in doing so, the current takes the following path (in red): http://img295.imageshack.us/img295/1018/ress7kr.png I traced only one path. Are you guys counting it as a different path when the current "turns" at...

It could very well come from a ammeter couldn't it? But that's not the case with this. Ok then, so the nodes are across R2. Current leaves from one end and enetrs at the opposite end. But for it to get there, it must first travel through the loop. I'm looking at the loop and I can see only one...

Since I'm finding resistance, I took the voltage source out. (Thevenin) Misunderstanding? Please correct me in that case.

Umm..so if the current splits at point A, then recombnines at point B, all the resisotrs between A and B are parallel then? But in that case (taking my original problem) Here is the circuit I get after shrinking. http://img312.imageshack.us/img312/6073/re26hs.png Even if I didnt shrink it, the...

Lets say that it didnt. Is there another method of breaking the problem down?

So when I shrink it, it looks like the two of them are in series. And R2 being parallel to them, yes? IF I were taking it across the R3 resistor, shrinking the wire between R1 and R2 shows that they are in series, and R3 is in series also?

yes. I'm taking it across R2. Why did you ask that question? Does that affect something?

Given the following circuit http://img499.imageshack.us/img499/4519/ress0ro.png How do you determine the total resistance? The book tells me the answer is R2 || (R1 + R3). How would I analyze the circuit to get that answer? I really can't see how R2 is in parallel with the rest.:cry: To me it...