Recent content by plain stupid

OK, so, what you're saying, in an oblique way, is to use these pseudoranges as defined in these equations, and simply "plug them into" receiver position equations, i.e. https://www.math.tamu.edu/~dallen/physics/gps/gps__20.png this thing, but we have these Pseudorange1,2,3,4 things (as in your...

So you're saying all satellites transmit the same 'restart point' at the same time, and this periodically repeats. From what I understand, and I don't understand much, (correct me if I'm wrong) you need the precise time of transmission to know the position of the satellite at that time (and...

I'm sorry, but this just furthers my confusion. Where exactly is this zero mark? The issue is, this PRNS is pseudorandom, which means it repeats, and which in turn means there isn't a single zero mark. Could you please suggest a source where there's more written about what you're saying? I'm...

I'm sorry, I'm still confused. This sounds like yet a third method, possibly. Could you clarify what you mean by "locking" and "relative phase"? Are you summarizing the method described on the website (https://www.e-education.psu.edu/geog862/node/1756)? )? That is, do you mean simply that...

I've been reading about this, but the sources I've consulted differ on what exactly is the case, fundamentally. I know this is a pretty basic question, but you'll see what I mean. In this () YouTube video, the professor (I assume) from Standard University explains (in the first 5 minutes of the...

Some notation: - the difference between the heights of mercury, which is effectively the height of the mercury in the open end of the tube is ##h_{diff}## - the volume of gas inside the sealed off end is ##V_{inside}## - the volume of gas when let outside, "normal volume", is ##V_{outside}## -...

Okay, I see. Thank you very much! I'm sorry for not realizing the hint in your first reply, and having you spell it out for me. Taking that into account, I get the right solution. I'll show a few steps below just in case someone else is interested. $$\rho_{Hg}gh_{theoretical} = \rho_{Hg}...

Should I try to play with my setup and get the result? I.e. am I on the right way (perhaps extracting that height of air and cancelling those terms in particular wasn't the right idea, but I should continue playing with something similar)?

I don't think there are any indications that the air is heated or that the temperature changes (I assumed an equilibrium state). Do you think this is actually pertinent considering how relatively basic this problem is? Yeah, by "actual" I did mean "theoretical", but if the barometer is faulty...

$$\rho_{Hg} gh_{actual} = \rho_{Hg} gh_{measured} + \rho_{air} gh_{air}$$ Note: by "actual", I mean "theoretical", i.e. what the barometer would measure were there no air inside it. By "measured" I mean "as measured by the faulty barometer, i.e. with some air introduced". I believe this...

I have a couple of basic questions/statements which I'm not sure about because I can't find a simple and comprehensive description of some of the basic stuff regarding the physical layer. (I've read the relevant chapters in a couple books like Tanenbaum's, and Kurose & Ross's one, but I couldn't...

Yes indeed. Thank you for "the numbers", they truly show the strength of the "electron repulsion is real" argument.

Alright. I was asking about current being the same throughout the whole circuit: that explained using a microscopic approach. However I didn't actually realize it's the application of Kirchoff's law, but a consequence of Ohm's law. Why it confused me is because I can't believe current is...

I don't see how classification is (ever) relevant?

That makes sense. Thank you very much. The thing is, I've actually finished the electric engineering intro and electronics course but this has bugged me since like the 8th grade... Yes indeed. Thank you for everything. :)