Recent content by planauts

  1. P

    Statistics Problem - Uniform Distribution

    Assuming that, I can get the rest of the problem. Once you get, F(x), you can take the derivative to get f(x). To get expected you integrate x*f(x) from 0,1 and x^2 * f(x) for the variance.However, I am still confused for the first part (i.e. the cumulative function). The max seems to throw me...
  2. P

    Statistics Problem - Uniform Distribution

    Hi, The question is: http://puu.sh/5GX2G.jpg http://puu.sh/5GX2G.jpg I am not exactly sure what the question is asking. Here is the answer/solution: http://puu.sh/5GX68.png But I am not sure what is going on. Could someone please explain what exactly the question is asking...
  3. P

    Solving z^5+16z'=0 in Complex Numbers

    I end up with. r^4e^{6i\theta} = -16 I know theta = -pi/2 and r = 2 would give a solution... How would I manipulate this equation so I can use the De Moivre theorem? Should I let 4w = 6theta So r^4*e^{4wi} = -16 Let p^4 = r*e^{wi} = -16 And then solve for p and change the w angles to theta...
  4. P

    Solving z^5+16z'=0 in Complex Numbers

    z^6 + 16|z|^2 = 0 (z^3+4|z|i)(z^3-4|z|i) = 0 Factor further using sum and differences of cubes? I'm not sure what you mean, r^5e^{5i\theta}+16re^{-i\theta}=0 r(r^4e^{5i\theta}+16e^{-i\theta})=0 r = 0
  5. P

    Solving z^5+16z'=0 in Complex Numbers

    Homework Statement Solve z^5 + 16 conjugate(z) = 0 for z element of C. z^5 + 16z' = 0 http://puu.sh/2EBqC.png Homework Equations The Attempt at a Solution My first thought was to use z = a+bi and z' = a-bi So: (a+bi)5 + 16*(a-bi) = 0 + 0i And then expand and simplify to the real and non real...
  6. P

    Understanding Toggle Flip-Flop Counter Sequence

    Thanks I understand (sort of). However, the solution says: 000, 001, 010, 111. You have 011 instead of 010?
  7. P

    Understanding Toggle Flip-Flop Counter Sequence

    Homework Statement http://puu.sh/2qUr7 Homework Equations The Attempt at a Solution http://puu.sh/2qUwc I know that Q0 goes toggles 1/0 every rising edge. And Q1 toggles 1/0 every rising edge of Q0. And Q2 toggles 1/0 every rising edge of Q1. But I don't understand how the...
  8. P

    Finite Difference (Interpolating Polynomial)

    Thanks a lot! It makes sense now. The question was so confusing but it is actually a very simple question! Thanks again everyone for your help.
  9. P

    Finite Difference (Interpolating Polynomial)

    http://puu.sh/1QMxk I'm still very confused about the "Then divide that by Δ^2x and take the limit as Δx→0." I got it simplified using CAS, and replaced Δx by h like you suggested. However, how do I convert that into an derivative. If I just take the limit as h->0, then it would be 0 and...
  10. P

    Finite Difference (Interpolating Polynomial)

    But the question asks for http://puu.sh/1QKd3 , and you are saying to divide http://puu.sh/1QKeC by http://puu.sh/1QKdV . The square is associated with x, rather than delta. Also, when I take the second difference of x, I get zero...
  11. P

    Finite Difference (Interpolating Polynomial)

    Homework Statement http://puu.sh/1QFsA Homework Equations The Attempt at a Solution I'm actually not sure how to do this question. How do i find Δx^2. I kind of understand the question but I don't know how to prove it. I know that Δy becomes dy when the width becomes...
  12. P

    Discrete Math: Proving a Homework Statement

    When I graphed it, i found out that r > 0.5 because 2^(-1) is 0.5 since n has to be int and -1 is an int but i don't know how to prove it. Graphing is not a good way, according to my Prof.
  13. P

    Discrete Math: Proving a Homework Statement

    No, I don't understand the second part with epsilon.
  14. P

    Discrete Math: Proving a Homework Statement

    Homework Statement http://puu.sh/1OfE2 Homework Equations The Attempt at a Solution I am not really sure about this one! :( I think it's 1 because http://puu.sh/1OfY0 http://puu.sh/1OfYE I came up the number by working backwards (assuming the conclusion is true). However, for a proof, I...
Back
Top