Recent content by Plutoniummatt

Homework Statement 2 protons collide at centre of mass energy of 7 TeV and produces a higgs with mass 100GeV and 2 protons: pp -> ppH calculate maximum energy of both protons in the final state The Attempt at a Solution Assuming higgs is produced at rest in lab frame (so...

hehe thanks, this is what happens when I look up a formula and not bother to read the text that goes with it :P but I assume you meant a2

Picture of the problem: As seen by the diagram above, a2 < a1 But the spherical Pythagorean theorem states that cos c = (cos a)(cos b). The triangle can either have a1,b,c or a2,b,c as its sides, which means the above equation contradicts itself. Am I missing something? thanks.

the initial velocity IS the maximum velocity, at equilibrium, KE = max, PE = zero. if you use your notation for the motion of the mass, ie the cosine term, then no, the phase is not zero, it has to be pi/2, because at T=0, psi must be zero because the mass is at equilibrium.

dont they multiply to give 1? e^{ i \phi}e^{- i \phi} = 1 Edit: you were right, i got it in the end taking into account the exponential factors...was a ***** of an algebra grindfest though

Homework Statement http://img716.imageshack.us/i/captur2e.png/ http://img716.imageshack.us/i/captur2e.png/ Homework Equations Stuck on the last part The Attempt at a Solution http://img689.imageshack.us/i/capturevz.png/ http://img689.imageshack.us/i/capturevz.png/

if you mean: [Lx, Ly] = LxLy - LyLx then it does not equal to zero, angular moment is the cross product: r x p so Lx = y.Pz - z.Py Ly = x.Pz - z.Px where x and y and z are position operators and Px, Py and Pz are momentum operators, stick those into your commutator and try again...

After everything, I got: M \ddot{x} + m \ddot{x} + ml \ddot{\theta}cos \theta - ml\dot{\theta}^2 sin\theta = 0 m \ddot{x} lcos\theta - m \dot{x} l \dot{\theta} sin \theta + ml^2 \ddot{\theta} - mglsin \theta = 0 how the heck can I solve this?

can I write the KE as: \frac{1}{2} m\dot{x}^2 + \frac{1}{2} ml^2\dot{\theta}^2 or do I have to write it as x and y components?

aha! you mean by the translation of the hanging mass as well as the swinging right?

am I? isnt that taken into account by the second term?

Homework Statement A block of mass M can move along a smooth horizontal track. Hanging from the block is a mass m on a light rod of length l that is free to move in a vertical plane that includes the line of motion of the block. Find the frequency and displacement patterns of the normal...

for B i used the transformation matrix: \frac{1}{\sqrt{2}}\begin{pmatrix} 1 & 1 \\1 & -1 \end{pmatrix} which means B = \frac{1}{2}\begin{pmatrix} 1 & 1 \\1 & -1 \end{pmatrix} \begin{pmatrix} 1 & 0 \\0 & -1 \end{pmatrix} \begin{pmatrix} 1 & 1 \\1 & -1 \end{pmatrix} which is...

yes my v_{\pm} would be: \frac{1}{\sqrt{2}} \begin{pmatrix} 1 \\ \pm 1 \end{pmatrix} so B would be \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} but I had to just look at it and see what numbers i should assign for B, is there a better way of doing it? oh and i got the...

\begin{pmatrix} 1 & 0\\0 & -1 \end{pmatrix} for A sorry i messed up the typing