Recent content by pmbasa

If you are not the bookish or bookworm type, try learning from someone you know is great at the subject :D

y = e^(x^(1/4)) x = e^(y^(1/4)) ln^x = y^1/4 y = (ln^x)^4 i guess you got it.. lol, i took a few seconds of my surfing time to solve it when you already got it.

1.) I'm still in high school. I run over some problems that I can't solve, but go back to it later or after a few days. I feel a litle frustrated and the same time challenged if I can't solve it. And the last option is to ask some help. 2.) No you don't. For me, being a mathematician is to...

hmm, man, I hate C++. C++ is way too overloaded (it's a joke). Try placing comments or exlanations on each part of your code, so you, yourself, and others know what a section does. Look at all those questions by KTC. Try simplifying your code, or remove code that isn't really needed. And I...

when u said that it is moving along with the x and y axes, did u mean that it was in the top view? I don't understand when you said that it rotated in the y direction (did you meant that i rolled forward) and rotated in the y direction (rolled sideward?). If you are using two vectors (x, y), you...

good one.. Nice explanation.

Well I guess, that is somehow quite problematic(to me). How do you mesure it? with a ruler? XD.. My point is, and I am sorry if i ddint point it out, that the coefficients (magnus, drag, lift, whatever!) can not be exactly determined by that formula. It is because the coefficients change along...

yeah, that was long. Good luck on ur learning :D

Hmm. Very interesting. Try out the experiment. That's the only way you can get an answer which you can trust, since you did the experiment.

Here is one way to look at it -- through the molecular level. I believe you know that a table is composed of billions of molecules. These molecules hold on to each other (the table is solid, duh) making the table compact. When you place a book on a table, the molecules of the table receives a...

I am just pointing out that the equation used for the coefficient of drag is not helpful unless u have the drag force, but u also need to find the drag force using the coefficient.. it's stupidly circular.. and I am really sorry if i keep using the word stupid and offending someone.. anyway...

I have searched a lot in the internet for the coefficient of drag, but to no avail.. All i found out is that u can achieve the coefficient by experimentation... the drag formula (Fd = 1/2 * Cd * rho * A * v^2) is correct. but the equation used in solving the drag coeficient is somewhat stupid to...

thanks again!

thanks a lot zyh, that was a real lot of help.. my research is only small scale.. i was planning to make a simulation in which the user inputs the initail values (speed, spin, position of the ball).. then the program simulates the path of the ball in 3d graphics.. i was wonderin if there are...

im currently looking for ping pong physics simulation in the web for my research.. i can't seem to find any which are useful.. im lookin for those that includes how the collision detection and modeling was handled, prog lang used, and graphics API for rendering(most i see are OpenGL), and the...