here what it says on the answer key
dy/dx = ( -1 / 1+(x^2+2)^2) 2x
dy/dx= -2x / 1+(x^2+2)^2
i've been trying to figure this problem for about 4hours already >.<
Homework Statement
find dy/dx in as simplified a form as possible
y = Cot-1 (x2 + 2)
Homework Equations
identities
derivatives
The Attempt at a Solution
dy/dx = -1 (cot-2(x2+2)(-csc2(x2+2)2x
dy/dx = (-1 (-csc2(x2+2)2x) / cot2(x2+2)
i also did the quotient rule for...
Homework Statement
find the dy/dx
of y = Sin4 x2 - Cos4 x2
Homework Equations
derivatives and identities
factoring
dy/dx (Sinx) = Cosx
dy/dx (Cosx) = -Sinx
The Attempt at a Solution
y = (Sin2 x2 - Cos2 x2) (Sin2 x2 + Cos2 x2)
im stuck at this part i don't know how to...
because the answer says
Since y=1/2 sin (4x), it follows that dy/dx = 1/2 cos 4x (4) = 2cos4x
i need to know how to get in this part
your calculation looks good but I am not sure where it came from
can you please explain it steps by steps
im sorry because I am still new at this lesson and i can't do it in my head yet
thank you!
the part that i get confuse would probably be multiplying trigo
yes its y= (sin 2x) (cos 2x)
however
ur answer does nnot match to the answer key
and also this part u did " 2(-sin 2x)(sin 2x) " isn't suppose to be -2(Sin24x)
btw the answer base on the book is
2cos4x and I am trying to figure out how to do it properly
btw thanks for trying my problem...
Homework Statement
y=(sin2x)(cos2)
Homework Equations
Product Rule for Derivatives
identities:
derivatives of
Sinx = Cosx
Cox = -Sinx
The Attempt at a Solution
i used the product and chain rule for derivatives then do the identities
y = sin2x*cos2x
dy/dx = (Cos2x)(2)...
uhm hi
i have an idea about ur problem
but i may not able to explain this well since I am really sleepy
so uhm ill just put the equation u have to use
mg*sin50 = 34
m is ur mass, g is 9.8m/s2, angle = 90-40=50
do the rest of calculation
if u want to make sure u have a correct...