Recent content by PMC_l0ver
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Derivative of the functionhelp
here what it says on the answer key dy/dx = ( -1 / 1+(x^2+2)^2) 2x dy/dx= -2x / 1+(x^2+2)^2 i've been trying to figure this problem for about 4hours already >.<- PMC_l0ver
- Post #6
- Forum: Calculus and Beyond Homework Help
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Derivative of the functionhelp
nope that i posted was right its based on my txt book please help me- PMC_l0ver
- Post #5
- Forum: Calculus and Beyond Homework Help
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Derivative of the functionhelp
ohh okay i get ur theory however the answer still wrong... its -2x / 1 + (x^2 +2)^2- PMC_l0ver
- Post #3
- Forum: Calculus and Beyond Homework Help
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Derivative of the functionhelp
Homework Statement find dy/dx in as simplified a form as possible y = Cot-1 (x2 + 2) Homework Equations identities derivatives The Attempt at a Solution dy/dx = -1 (cot-2(x2+2)(-csc2(x2+2)2x dy/dx = (-1 (-csc2(x2+2)2x) / cot2(x2+2) i also did the quotient rule for...- PMC_l0ver
- Thread
- Derivative
- Replies: 6
- Forum: Calculus and Beyond Homework Help
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Derivatives of Trigonometric Function
ohh ok thank you! i got it- PMC_l0ver
- Post #3
- Forum: Calculus and Beyond Homework Help
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Derivatives of Trigonometric Function
Homework Statement find the dy/dx of y = Sin4 x2 - Cos4 x2 Homework Equations derivatives and identities factoring dy/dx (Sinx) = Cosx dy/dx (Cosx) = -Sinx The Attempt at a Solution y = (Sin2 x2 - Cos2 x2) (Sin2 x2 + Cos2 x2) im stuck at this part i don't know how to...- PMC_l0ver
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- Derivatives Function Trigonometric
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Derivatives of Trigonometric Function
ohhh ok i see thank you! i totally forgot about this trigonometric formula thank you so much! it refreshed everything!- PMC_l0ver
- Post #9
- Forum: Calculus and Beyond Homework Help
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Derivatives of Trigonometric Function
because the answer says Since y=1/2 sin (4x), it follows that dy/dx = 1/2 cos 4x (4) = 2cos4x i need to know how to get in this part your calculation looks good but I am not sure where it came from- PMC_l0ver
- Post #7
- Forum: Calculus and Beyond Homework Help
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Derivatives of Trigonometric Function
can you please explain it steps by steps im sorry because I am still new at this lesson and i can't do it in my head yet thank you! the part that i get confuse would probably be multiplying trigo- PMC_l0ver
- Post #5
- Forum: Calculus and Beyond Homework Help
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Derivatives of Trigonometric Function
yes its y= (sin 2x) (cos 2x) however ur answer does nnot match to the answer key and also this part u did " 2(-sin 2x)(sin 2x) " isn't suppose to be -2(Sin24x) btw the answer base on the book is 2cos4x and I am trying to figure out how to do it properly btw thanks for trying my problem...- PMC_l0ver
- Post #3
- Forum: Calculus and Beyond Homework Help
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Derivatives of Trigonometric Function
Homework Statement y=(sin2x)(cos2) Homework Equations Product Rule for Derivatives identities: derivatives of Sinx = Cosx Cox = -Sinx The Attempt at a Solution i used the product and chain rule for derivatives then do the identities y = sin2x*cos2x dy/dx = (Cos2x)(2)...- PMC_l0ver
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- Derivatives Function Trigonometric
- Replies: 8
- Forum: Calculus and Beyond Homework Help
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Calculating Mass of Light Fixture from Cable Tensions
uhm hi i have an idea about ur problem but i may not able to explain this well since I am really sleepy so uhm ill just put the equation u have to use mg*sin50 = 34 m is ur mass, g is 9.8m/s2, angle = 90-40=50 do the rest of calculation if u want to make sure u have a correct...- PMC_l0ver
- Post #8
- Forum: Introductory Physics Homework Help