Recent content by pointintime

by the way the circles touch

Trig Problems please help please! Homework Statement A surveillance satellite circles Earht at a height of h miles above the surface. Suppose that d is the distance, in miles, on the sruface of Earth that can be observed fromt eh satellite. See the illustration. (a) Find an equation...

can you answer my question in #3

ok hmmm m2 g = m1 (acceleration radial) so then if this is the correct equation my question... is how do you know when to consider the masses as a system and when not to? net force = mass times acceleration by deffintion it dosen\'t mean this necessarily net force = net...

Homework Statement ok well then... we did a lab were you have a hanging mass attached to a stirng that went through a straw and was attached to a rubber stopper. The lab was to find the mass of the rubber stopper once you know the velocity. So I was woundering if this looks correct...

i guess i need some assistance with da math x^-2 m1 = (3.84 E 8 m - x)^-2 m2

now what x + m1^-2 x m2^2 = m1^-2 (3.84 E 8 m) m2^2

yes m is meters

ok so I got down to this x = sqrt( ((m1 + m2)(3.84 E 8))/m2 ) which gave me the wrong answer

m2 = masss of Earth m1 = mass of moon

m3 = mass of satalite (G m3 m2)/x^2 = (G m3 m1)/(3.84 E 8 m - x)^2 I can cancel out the m3 and the G right?

how are you suppose to do this how come the mass of the satalite dosen't cancel out

a = Rm1^-1 G m1 = (3.84 E 8 m - Rm1 )^-1 G m2 = 0 I need help rearanging for Rm1 i got his Rm1 = (m2 - 1)^-1 (3.84 E 8 m) m1

ok then mass m1 is earth mass m2 is moon mass satalite is m3 radius satalite to Earth is Rm1 radius satalite to moon is Rm2 net force acting on m3 on radial direction = m3 (acceleration in radial direction) = 0 = Force of gravity exerted on m3 by m1 = force of gravity exerted on m3 by m2...

I don't see how know the radius from Earth to moon is about 3.84 E 8 meters helps