Recent content by poohbear1986

P=13+45*ln*x represents the percentage of inbound e-mail in the U.S. that is considered spam, where x is the number of years after 2000. say you use 2003, i keep figurin out this out and i get 12.18 and 5.045, i like to have someone tell me if I am right or wrong

thank you that was driving me nuts

thank you i apprecite the help immensely

ok i was graphing y=-e^x e=2.1783 and i got this up and down line growing from negative to positve, i have no clue what the hell I am looking at, I've attached what i got tell if I am right or wrong, point in the right direction if you could

so i can have a negative exponet, and it all still will be real numbers

heres a question I am trying to figure out if this equations domain f(t)=4.5e^t where e is 2.1783 im thinking that the answer is all positve numbers. because it can't equal zero so all negative numbers cause it to be 0

asymptotes horizontal and vertical f(x)= 2x+3/x+2 f(x)=5x/x^2+1

Consider the function f(x)=x^2+4x+1 a)Find h, the x-coordinate of the vertex of this parabola.

ok i think i get it now, so my answer would be 2.25, put that into millions and i get 2,250,000

isnt the x in front of the C a 60 so to get C by itself you divide

this is what i did C(X)=1.5X/100-X C(60)=1.5*60/100-60 C(60)=90/40 C(60)=2.25 C(60/60)=2.25/60 C=.0375 OR .04 so I'm suppose to put this in millions if i move the decimal point over six spaces then i get37,500 or 40,000

i did that a got like .04 but to me that doesn't seem right

C(x)=1.5x/100-x his is the formula the book gives me

thanks a lot i finally understand what I'm looking at, i appreciate the help

so if i multiply both sides by 1/3 i should get what I'm looking for