@AntiStrange : I have calculated the equation, and I find the my answer is the same as the answer key assuming that the collision is inelastic ( tow particles moving together ). My hypothesis is that you made a mathematics mistake ( equation mistake ) .
@tms : We can't do this question without...
or, use this EASIER way :
for the first condition, and the second condition, the gravitational constant is always the same.
G=G
You have known what the value of F is :
F=\frac{GMm}{r^2 }
and, the value of G is :
G=\frac{Fr^2 }{Mm}
you can make it like this :
G=G
\frac{Fr1^2...
The tension force of the string which coincide with the length of the string. It didn't make any difference of distance with the axis, so, it didn't loss any energy.
The formula is correct.
It's derived from :
The acceleration of the mass ( thing ) is determined by \frac{Fx}{m}.
The force acting on the mass is only -Fk.
So, the acceleration of the mass is -g*\mu k...1
So ( input the first equation ) :
v' = v + a*t
t = \frac{V}{g*\mu k}...2
And
s =...