Recent content by quanjia

Thank you,reilly and StatMechGuy. You reply help me greatly. But when we deal with delta potential,why we consider the wave function continuous at x=0 where the potential is infinite and the differential of the wave function is discontinuous? Is it just for simplity in analyse and calculate.

I'm sorry that I can't catch you whole meaning exactly. Let me construct an example as follow (f(x) is the wave function over x): When 0<x<1/2, f(x)=e^(i*x), when 1/2<x<1, f(x)= -2x+2, and otherwise, f(x)=0. there is only one singularity at x=1/2 with the absolute value is 1...

I think it needn't be continuous even if the probability should. Wave function can be complex while probability is its absolute value.:bugeye:

The definition of "bar" is integrating{(complex conjugate of[f(x)]) *g(x)} over x, when <f(x)| hit |g(x)>. So <aA| equal the complex conjugate of a multiplying <A|. The definition is used in J.Griffiths's 《Introduction to Quantum Mechanics》.