Recent content by raiderUM

You are correct. I miss labeled it. This would not affect the answers

Homework Statement Again, I have a question where I have not idea what I did wrong... Please give suggestions! Thanks. Work is shown on attachment. You have a foundation wall system in the field that you were asked to determine the load capacity of per lineal foot. The wall has the...

The distance from P was not given, its what I calculated and solved for when I did my reactions. I did the bending stresses and calculations this is what I came up with: Fb=1550 fb=M/S =417.92psi M=50652 S=121.2 So by my calculations it would hold

The 5.75 is the distance "P" Is from the R2 reaction or 4.25 from R1. 16075 is the load "P" in lbs plus the 1000#/1 on the beam that gives me my reactions on R1and R2. Bending stress is fb? Allowable is Fb? I think I maybe over thinking this problem

This is what I've came up with: By adding 16,075# 5.75ft from R2 R1(10)+2000(1)=16075(5.75)+10000(5) R1=14043.125 R2=14031.875 Fc allowable is 730 for Dense No1 729.51=14043.125/(3.5)(5.5) for R1 728.93=14031.875/(3.5)(5.5) for R2 So am I getting the correct answer?? Max...

for a three phase motor all you need to do is switch any two phases and your good. For "some" single phase motors you can reverse them, usually you switch two internal wires. There will be a sticker on the outside of the motor somewhere or on the wiring diagram.

Homework Statement Dense No 1 grade of Douglas Fir-Larch, 6x12 is to be used as a simple beam spanning 10 feet with a 2 feet overhang. The beam has the loading shown in the sketch I've attached. Determine the maximum value of the concentrated load "P" to maintain the structural integrity...

So the Live load is just Area(LL)=Area(DL), which equals 1120. So M=WL/8 and V=W/2 M=2240 V=560 No 1 lumber Fb=1000 No 2 lumber Fb=900 S=M/Fb 2240(12)/1000 = 26.88 in^3 2240(12)/900 = 29.87 in^3 Which the table says 2x12 in both lumber sizes will cover it

Homework Statement Rafters are to be used on 24in centers for a roof span of 16ft. Live load is 20psf (without snow) and the dead load is 15psf, including the weight of the rafters. Find the rafter size required for Douglas fir-larch of No 1 grade and No 2 grade, based on bending stress...

I am not getting the correct answer for FORCE. F=stress(Area) Am I messing up the Area some how?? The answer is suppose to be 86KN of Force or 19,333lb

Homework Statement What Force must be applied to a steel bar, 1in [25.4mm] square and 2ft [610mm] long, to produce an elongation of .016in. [.4064mm]? Homework Equations L=610mm ΔL=.4064mm E=29,000,000 The Attempt at a Solution What I know is: E=Stress/Strain...

Still have not found out what the problem is. Can't do the power quality test till next fall because the Chillers never shut off until outside temp is below 50 degrees. But PF is very good for now.

The City has a power quality meter that we are going to hook up to the transformer on the secondary side to see what readings we are truly getting. I'm glad you guys see what I am talking about now. We have poor power factor in a lot of buildings and I am trying to correct that, but this is...

This is all the information I have. It shows the data for Month to date on KW, PF trending, and real-time PF

I would say that the EMON is wired correctly. I have over 150 of these devices at various locations. I am not getting an errors saying the CT's are backwards or installed incorrect