Recent content by RajarshiB91

So, Δu=CvdT and ΔP=RΔT/v. The ΔT cancels out again if I put Δh=0. I still don't see how I can get ΔT from just Δh=0.

But if you put only Δh=0, so the equation is then Δu+PΔν=0. But Δv=0 assuming it is incompressible. So, we get only Δu=0. Then how do I solve the problem?

Thanks BvU. Yes, I googled similar problems and understood what needs to be done. By displacing the block by θ I calculate the new CM height which comes out to be h=Rcosθ+Rθsinθ+2cosθ Now, it is just differentiating twice. So, for...

Homework Statement A homogeneous wooden bar of length 10 cm, thickness 4 cm and weight 1 Kg is balanced on the top of a semicircular cylinder of radius R as shown below. Calculate the minimum radius of the semicircular cylinder if the wooden bar is at stable...

Hi Chet, thanks for your reply. Yeah, I had a brief introduction to it a long time back. I read it again and I think I have solved the problem. Basically, all the terms cancel out and we are left with the following equation: Q=m(h2-h1) where enthalpy per unit mass h=u+Pv...

Homework Statement [/B] A molten metal is forced through a cylindrical die at a pressure of 168000 Kg per square meter. Given that the density of the molten metal is 2000 Kg per cubic meter and the specific heat of the metal is 0.03, find the rise in temperature during...