Recent content by rajathjackson

My understanding was that processes which can't proceed in the reverse direction without any external intervention are called as irreversible processes. But, you mentioned that even if there is an external energy source that process can be reversible. So, what is it that actually makes a process...

So. if even processes in which we use an external source of energy is reversible which all processes are called irreversible and on the basis of what are they called so?

But, according to 2nd law of thermodynamics heat doesn't flow from a cold to a hot body without any external work done on it. So, cooling of a body is an irreversible process because a body doesn't get hot on its own. We need to heat it up with an external source of energy.

The equation for entropy S=delta(Q)/T is derived from reversible processes such as Carnot cycle. The delta(Q) in the equation is the reversible heat added or taken out from the system. So, why is this equation valid in the case of processes like cooling of a body which is irreversible?

Yeah, now I understand my mistake. Thanks.

But, only the horizontal component of the velocity would contribute toward range. That's why I took ucosθ instead of u. My aim is to make the expression in terms of just one variable to differentiate the equation and find the maximum value.

First term is the range covered in a normal projectile motion and second term is time taken to fall through a height h multiplied by the horizontal velocity.

Homework Statement A particle is projected with an initial speed u from a point at a height h from the horizontal plane. Find the equation for maximum range of the particle. Homework Equations R=u^2sin2θ/g H=(usinθ)^2/2g The...

Q: The motion of a body is given by the equation dv/dt=6-3v.If the body was at rest at t=0 then: The speed is 1m/s when the acceleration is half of the initial value. (True/False) My approach: At t=0 the acceleration of the particle is 6m/s^2.Therefore...