Recent content by RanTanPlan

Anyway, thanks for the help everyone!

Ah okay, so I'm looking for the biggest slope..

Ok, thanks. Oh boy, it's been a long time since I have differentiated anything. So say I differentiate f(x)=ax+b for the part where the accelleration increases and get f'(x)=a because the rate of change in the accelleration is 0. Hmm, guess I'm not sure what I'm looking for..

Gneill: I see, thanks for the suggestion, might check that out. Right! but is this what you would call an angular accelleration profile? BvU: Ok, so I guess I need to find the higest accelleration to multiply with moment of inertia?

Gneill: Ah okay. I actually don't know about the detection of position...might be motion control. BvU: Yes exactly. You mean like F=m*a? "You need moment of inertia - as provided in link in #3" Ok, let's say I have the moment of inertia through the red rotation axis and the accelleration. Is...

Oh, I see I also wrote the cylinder is 30 cm, it is 20 cm.

Right, it has to turn 90 deg. then stop entireIy and later turn the opposite way. I don't understand how 15 rpm becomes 1/60 of a second? I figured it would be 1 sec to make a quarter-turn at 15 rpm? Sorry, I shouldn't have been stingy with the units: The 0,1 is just half the length of the...

Sure thing, I realize I asked a too, ah, open question. Well here is my attempt: Weight of cylinder: 20 kg (evenly distributed load) Lenght of cylinder: 30 cm I guess I need a speed of about 15 rpm.

It's a massive cylinder. Oh, I missed there was a homework forum, thanks!

Ah, it's a school assignment

Thanks for your replies and links. I have only tried to calculate bending moment. I have no idea how to calculate torque so I am not familiar with the equations. I expect I will need to know the weight of the cylinder, the speed as you mention and maybe moment of inertia of the cylinder. "This...

<< Mentor Note -- thread moved to the schoolwork forums after we found out this is really a homework assignment >>[/color] Hi, I've got a cylinder which needs to turn 90 deg. clockwise and 90 deg. counterclockwise (seen below from the front and above). How do I calculate the necessary torque on...