Recent content by RaptorsFan
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Calculus I - Double Derivitive
Homework Statement Find dy/dx and d^2y/dx^2 y = x / (x^(2)+1)Homework Equations d/dx (f/g) = (g d/dx f - f d/dx g) / g^2 The Attempt at a Solution Finding d/dx: d/dx y = (x^(2)+1) d/dx (x) - (x) d/dx (x^(2) + 1) / (x^(2)+1)^2 = (x^2 + 1) - (2x^2) / (x^(2)+1)^2 So that's my first...- RaptorsFan
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- Calculus calculus i
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Differentiation, Product Rule 3-terms
Thank you for the quick response.. much appreciated.- RaptorsFan
- Post #3
- Forum: Calculus and Beyond Homework Help
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Differentiation, Product Rule 3-terms
Homework Statement f(x) = (2x-1)(3x-2)(5x+1) d/dx = ? Note that I am letting (2x-1)(3x-2) = f and 5x+1 = g Homework Equations d/dx (fg) = f d/dx g + g d/dx f The Attempt at a Solution d/dx y = (2x-1)(3x-2)d/dx(5x+1)+(5x+1)d/dx((2x-1)(3x-2)) = (2x-1)(3x-2)(5)+...- RaptorsFan
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- Differentiation Product Product rule
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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What is the derivative of sin2x / (sin2x + secx) with respect to x?
Ahh yes I understand, just working it out on paper for myself now. Thank you- RaptorsFan
- Post #10
- Forum: Calculus and Beyond Homework Help
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What is the derivative of sin2x / (sin2x + secx) with respect to x?
Thank you. d/dx sin2x + d/dx secx = cos2x (d/dx 2x) + tanx*secx Ahh, I see my fault.. the correct solution would be: = [2(sin2x + secx) cosx - 2sin2x cos2x + (secx*tanx)] / (sin2x + secx)^2 Thank you, I always make stupid mistakes. Is this the answer you are thinking on?- RaptorsFan
- Post #7
- Forum: Calculus and Beyond Homework Help
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What is the derivative of sin2x / (sin2x + secx) with respect to x?
Yes sir, that is correct. But I am skipping a step. d/dx (sin2x + secx) is equal to d/dx sin2x + d/dx secx I just failed to put that step in, would you agree with this?- RaptorsFan
- Post #5
- Forum: Calculus and Beyond Homework Help
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What is the derivative of sin2x / (sin2x + secx) with respect to x?
On our given formulae sheet sec x is equal to sec x * tan x :S- RaptorsFan
- Post #3
- Forum: Calculus and Beyond Homework Help
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What is the derivative of sin2x / (sin2x + secx) with respect to x?
Homework Statement sin2x / (sin2x + secx) d/dx = ? Homework Equations d/dx (f/g) = (g d/dx f - f d/dx g) / g^2 d/dx sec u = sec u tan u d/dx u d/dx cos u = -sin u d/dx u d/dx sin u = cos u d/dx u The Attempt at a Solution d/dx y= [(sin2x + secx) d/dx (sin2x) - sin2x d/dx...- RaptorsFan
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- Calculus calculus i
- Replies: 9
- Forum: Calculus and Beyond Homework Help
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How do I differentiate (x^(3)+2x) / (x^(2)-5)?
Yep that was a careless typing error, thank you for validating.- RaptorsFan
- Post #4
- Forum: Calculus and Beyond Homework Help
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How do I differentiate (x^(3)+2x) / (x^(2)-5)?
Homework Statement (x^(3)+2x) / (x^(2)-5) d/dx = ? Homework Equations d/dx (f/g) = (g d/dx (f) - f d/dx (g)) / g^2 The Attempt at a Solution d/dx y = { (x^(2)-5) d/dx (x^(3)+2x) - (x^(3)+2x) d/dx (x^(2)-5) } / (x^(2)-5)^2 This is where it gets complicated for me. {...- RaptorsFan
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- Calculus calculus i Differentiation
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Limits in 0/0 Calculus I Problem
After about 10 attempts later and numerous sign errors and not simplifying stuff enough i finally got an answer of -1/4.. Thanks anyway guys!- RaptorsFan
- Post #3
- Forum: Calculus and Beyond Homework Help
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Limits in 0/0 Calculus I Problem
Homework Statement I'm in the early stages of Calculus I.. just doing the basics you learn in the Calc prep course. This one problem is really getting me confused. Homework Equations Lim -> 0 in the function 1/x(1/(x+2)^2 -1/4) The Attempt at a Solution I've tried foiling...- RaptorsFan
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- Limits
- Replies: 4
- Forum: Calculus and Beyond Homework Help