Recent content by rbn251

yup f*s sry for bothering!

haha I think you're right - typo in the textbook!

As far are I know everything is correct 'mathematically'. You are right about the brackets but I have used the equation correctly in both cases as such.

Homework Statement Two rockets A and B are moving away from the Earth in opposite directions at 0.85c and -0.75c respectively. How fast does A measure B to be travelling? Now I have worked out v = -0.85-0.75/(1- -0.85*-0.75) = -0.997. This is correct. Now I would like to work it out backwards...

Homework Statement A rectangular loop of wire, of sides 5 and 3 cm moves away from a a long straight wire at 4ms-1 carrying a current of 2 amps. What is the EMF induced in the moving loop, when the near side of the loop is 3cm away from the wire? Homework Equations B = μ0I/2πr EMF = -dΦ/dt...

You are right, this is confusing. Really you don't want to consider the direction of the rope wrt the diagram, but wrt the truck. So there are only really two directions the rope moves - to the right or to the left. (Think about 'unwinding' the rope from the pulleys, and consider it as a...

The other part I have worked out as: If block B rises by x, then the string length at the truck increases by x. If block A rises by y, then the string length at the truck increases by 2y. Let the string length at the truck be z, then z=x+2y. Differentiating this relation twice, and sub in the...

Hi, I have also been trying to solve this problem, using the string length method: If the weight on the left moves up by x, then the string segment on the left decreases by x. If the weight on the right moves up by y, then the string segment in the middle decreases by y and the string segment...

Kl, thanks So for initial speed of √200 and mass=1, k=1, KE=1/2*1*200 = 100J. From the position (I assume we need to shift to -10 and not use 0) PE=1/2*k*(-10)^2 = 50J So total is always 150J and PE on its own is 150J when x=+/- 17.3 However, the specific question this is from...

Does anyone know how the mathematics/formulae of SHM (say a particle in a force field, with the standard a=-d) changes when the particle is given an initial velocity independent of the force causing SHM? For example in 1D say we have a graph of acceleration-displacement in the standard form...

Ah, I see now, thanks!

But surely there is a starting height and equivalent speed of entry to the loop at which it just makes it to the top, it's speed drops to zero, and it falls vertically down? Can you explain why this is not possilbe?

Ah, so is it not possible that the trolley can get to the exact top and stop? It either keeps going round, or never gets there? For the original question let's assume that the track cannot pull.

The track pushes you towards the middle??

You now have some sort of inertia in the upwards direction? sorry I don't know.