So now the limit is 0 if I use the Squeezing Theorem for the numerator, and the "lim sinx/x=0" for the denominator? Am I thinking about this correctly or am I just trying to plug and play?
Homework Statement
(a) Explain why L'Hopital's rule does not apply to the problem
lim_{x\rightarrow0} [ (x^{2}sin(1/x)) / sinx ]
(b) Find the limit.
Homework Equations
lim _{x\rightarrow0} xsin(1/x) = 0 , by the Squeezing Theorem.
lim _{x\rightarrow0} sin (1/x) Does Not Exist...
Homework Statement
"On a certain clock the minute had is 4in long, and the hour hand is 3in long. How fast is the distance between the tips of the hands changing at 9 o'clock?"
Homework Equations
- a^{2} + b^{2} = c^{2}
- Law of Cosines?
The Attempt at a Solution
Ok i drew a clock...