Recent content by redone632
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What is the probability that Mike Mouse will be included in the control group?
Hmm, I never really thought of it like that. So my original answer was correct? (1C1 * 8C3) / 9C4- redone632
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- Forum: Precalculus Mathematics Homework Help
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What is the probability that Mike Mouse will be included in the control group?
I don't understand why you chose 4C1 and 5C3. The way I thought of it was just like any other Hypergeometric problem. For example, you have a bag of 9 marbles, 1 black and 8 white. What is the probably that you will get the black marble when you pick 4 marbles without replacement. So there is 1...- redone632
- Post #3
- Forum: Precalculus Mathematics Homework Help
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What is the probability that Mike Mouse will be included in the control group?
Homework Statement Suppose 9 mice are available for a study of a possible carcinogen and 4 of them will form a control group (i.e. will not receive the substance). Assuming that a random sample of 4 mice are selected, what is the probability that a particular mouse, Mike Mouse will be included...- redone632
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- Hypergeometric
- Replies: 5
- Forum: Precalculus Mathematics Homework Help
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Compact sets are covered by finitely many epsilon disks
That's what I thought. We've just been dealing with defining epsilon so much I want to be sure. I'll go over my notes to see if I can come up with something. Thanks!- redone632
- Post #5
- Forum: Calculus and Beyond Homework Help
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Compact sets are covered by finitely many epsilon disks
Alright, but how do I go about defining my epsilons to be?- redone632
- Post #3
- Forum: Calculus and Beyond Homework Help
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Compact sets are covered by finitely many epsilon disks
Homework Statement Let K be a compact sebset of a metric space (X, d) and let \epsilon greater than 0. Prove that there exists finitely many points x_1 x_2, ... x_n \in K such that K is a subset of the union of the \epsilon neighborhoods about x_i Homework Equations N/A The Attempt...- redone632
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- Compact Epsilon Sets
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Open subsets are a union of disjoint open intervals
Hmmm, I think I've made some development but I'm still unsure how solid it is. Let E be an open subset of \Real. Define the equivalence relation x \sim y \Longleftrightarrow \exists (a,b) such that {x,y} \in (a,b) \subseteq E. The equivalence classes will be distinct. By the archimedean...- redone632
- Post #3
- Forum: Calculus and Beyond Homework Help
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Open subsets are a union of disjoint open intervals
Homework Statement Prove that any open subset of \Real can be written as an at most countable union of disjoint open intervals. Homework Equations An at most countable set is either finite or infinitely countable. The Attempt at a Solution It seems very intuitive but I am at lost...- redone632
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- intervals Subsets Union
- Replies: 2
- Forum: Calculus and Beyond Homework Help
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Finite subgroups of unique orders are normal
Oh wow, I swear I miss the most obvious things. Thanks for your help again!- redone632
- Post #5
- Forum: Calculus and Beyond Homework Help
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Finite subgroups of unique orders are normal
Since H is a subgroup of order m, xHx^(-1) will be a subgroup of order m. Since H is the only subgroup of order m there will be no other subgroup such that xKx^(-1) is of order m. Therefore, xHx^(-1) = H. I think that's it, but I can't connect the dots to the last statement.- redone632
- Post #3
- Forum: Calculus and Beyond Homework Help
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Finite subgroups of unique orders are normal
Homework Statement Let G be a finite group and H a subgroup of G having order m. Show that if H is the only subgroup of order m in G, then H is normal in G. Homework Equations A subgroup H of G is normal in G if and only if xHx^{-1} \subseteq H \forall x \in G The Attempt at a...- redone632
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- Finite Normal
- Replies: 4
- Forum: Calculus and Beyond Homework Help
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Abelian groups of order 70 are cyclic
Awesome. Thanks!- redone632
- Post #5
- Forum: Calculus and Beyond Homework Help
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Abelian groups of order 70 are cyclic
Hmmm I think I got it. I just want to make sure it's right. Since 2, 5, 7 are primes that divide 70. Then by Cauchy's Theorem there must be an elements of order 2, 5, 7 say, a, b, c respectively. Since G is abelian, then every subgroup must be normal. Therefore, the subgroups generated a, b, c...- redone632
- Post #3
- Forum: Calculus and Beyond Homework Help
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Abelian groups of order 70 are cyclic
Homework Statement Show that every abelian group of order 70 is cyclic.Homework Equations Cannot use the Fundamental Theorem of Finite Abelian Groups.The Attempt at a Solution I've tried to prove the contrapositive and suppose that it is not cyclic then it cannot be abelian. But that has lead...- redone632
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- Cyclic Groups
- Replies: 5
- Forum: Calculus and Beyond Homework Help