Recent content by redsealelectron

Homework Statement We are working with phasors and R-L-C circuits. Here is some given data: Vsource = 120 Volts, 60 Hz Resistor = 100\Omega Capacitor = 50\muF Inductor = 0.2 H Inductor Resistance = 10\Omega My question is this, when solving for current using V = IZ, can you set...

Dick, thank you for your help and letting me work through the problem. I have a better understanding now.

Its multiplied by 16, because the length has increased by four and the area has decreased by four, initial resistance * the decreased area of four * the increased length of four?

So the wire is now four times longer, and is now thinner then it was orginally. The cross sectional area is smaller therefore the resistance is higher then it was. So i must use R = p(L/A)? will I have to solve for the diameter of the wire?

Increasing the length increases the resistance of the wire by a factor of four. If the cross sectional area increases by a factor of four then the resistance should decrease by a factor of 16... this would be r2 = 1/4R1?

Homework Statement A piece of aluminum wire has a resistance of 20C, 15.5 \Omega. If this wire is melted down and used to produce a second wire having a length four times the original length, what will the resistance of the new wire be at 20C? (Hint: The volume remains the same)...