Recent content by reedy

im not sure of what a bounded function is, but you made me think: lim cos x / x = lim cos x * lim 1/x since lim 1/x is 0, lim cos x / x should be 0 as well. right? great stuff - thanks!

But what do I do about cos x/x as x--> inf? That isn't a limit I'm familiar with. My sources say it's 0, but is there any proof?

Im trying to find lim (2x+cos x)/x as x --> inf. I've started out by multiplying with the conjugate. [(2x+cos x)(2x-cos x)] / x(2x-cos x) = =(4x2-cos2x)/(2x2-x cos x) But now I'm lost - any hints?

Ahh, perfect. Now I see it - thanks a bunch!

Of course! What was I thinking... But if that is true, which it is, wouldn't it be easier to just use the fact that and pull out the normal from L's equation, (2,1,-3), and establish that the plane's equation is 2x1+x2-3x3? If so, I would need a right hand side as well. And the only...

I have two given points. A=(-1,2,3) and B=(3,4,-3). I want to find all points (x1,x2,x3) that have the same distance to A and B. Attempt: I think finding the line they both lie on is a good first step. To do this, I've drawn a vector between A and B, and found the line's equation...

Ohh, you mean like that. Sorry! Well, sin(3\pi)=0 sin(2\pi)=0 sin(1\pi)=0 and cos(1\pi)=-1 cos(2\pi)=1 cos(3\pi)=-1 So what you initially said was indeed correct, and the functions do indeed cross when x is odd; -1, 1, etc. But how does this help me solve the equation...

Ohh, right. My bad. C=sqrt(2) and didn't even think of the radian/degree thing. That leaves us with arctan(B/A)=1^\circ\Longleftrightarrow \frac{\pi}{4}rad=\phi So let's break this down. C(cos(\phi)sin(u) - sin(\phi)cos(u))\Longleftrightarrow \\ C*sin(\phi-u)\Longleftrightarrow \\...

I thought it would help... sin(-\pi x)-sin(\frac{\pi}{2}+\pi x)=1 Because if they're all sine, maybe I could do the following: -\pi x-\frac{\pi}{2}+\pi x=90 But that means I could cross out -PI*x which would leave me with -PI/2=90. :frown: -------- Putting your tip to use, C=1 in my case...

I'm sorry, I'm not sure I got that completely. How does sine and cosine of an odd integer differ from sine and cosine of an even integer? Is there a rule I'm not aware of? I do see that the lines cross at x_1=-1,x_2=-\frac{1}{2},x_3=1,x_4=1\frac{1}{2} but that is pretty much all I know...

The problem is finding the points of intersection for two given functions. f1=sin(-\pi*x) f2=1+cos(-\pi*x) I've plotted the functions using Maple. http://dl.getdropbox.com/u/12485/plot.png And I'm quite certain that to find the points of intersection, I have to set f1=f2 which...

I was thinking of the algebra behind it and... K=\frac{0,855*1*0,855*1}{0,145*1*1,15*1} K=\frac{0,855*0,5*0,855*0,5}{0,145*0,5*1,15*0,5} Since you apply the same volume to all the factors, they cancel each other out. It's the amount of substance that makes the eq. constant...

So as long as I'm consistent, it doesn't matter how much I use? In that case, I'll go for a liter, as you mentioned. No division needed. ________________________________|H2_____|CO2____|H2O______|CO Amount of substance at start____|1______|2______|0________|0...

I start with 1 mol H2 and 2 mol CO2. At one point, 85,5% of the hydrogen turned into water. They want the eq. constant of the following reaction: H_2(g) + CO_2(g) \rightleftharpoons H_2O(g) + CO(g) ________________________________|H2_____|CO2____|H2O______|CO Amount of substance at...

Assignments given to me are drawn up in this manor: There is 1,34 mol of X, 1,69 mol of Y and 1,95 mol of Z at equilibrium. Calculate the equilibrium constant for the following reaction: 2X + Y_2 \rightleftharpoons 2XY or sometimes the coefficients are left out in the equilbrium equation...