Something seems off about that because if I say A = 1, then
$$A(1-ω^2) - B = 0 $$ $$→$$ $$B=(1-ω^2)$$
And
$$C(1-ω^2) - B = 0$$ $$→$$ $$C = B/(1-ω^2) = (1-ω^2)/(1-ω^2) = 1 $$
But I still have the equation for $$B(2-ω^2) - A - C = B(2-ω^2) - 2 = 0$$ $$→$$ $$B=2/(2-ω^2)$$ which will give me...
Is there another method that you know of? Can I set up a ratio of the amplitudes? My equations after assuming a solution of
X1,2,3 = Asinωt, Bsinωt, and Csinωt are
$$ A(1-ω^2) - B = 0$$
$$
B(2-ω^2) - A - C = 0
$$
$$
C(1-ω^2) - B = 0 $$
1. Homework Statement
A short metal cylinder 145 mm in diameter and 145 mm high at 1045 K
is suddenly exposed (all sides exposed) to a room air temperature at
300 K with h=25 W/m².K. Assume that for the metal k=40W/m.K, den=7800 kg/m3
and Cp=c=600 J/kg.K. Estimate (a) the time required for...
Am I supposed to use the humidity ratio to solve this? I thought the 0.1 kg/s was the mass flow rate of dry air
ω = 0.622 x (Saturated Pressure)/ (Pressure mixture - Saturated Pressure)
The saturation pressure at that temperature is 9.14 kPa using linear interpolation with the saturation tables. Ok, so the rate given was for the mixture which is the same for all components. For some reason, I was thinking each component might have a different mass flow rate.
Then the part I'm...
1. Homework Statement
Only Number 1, not number 2
2. Homework Equations
Dew Point Temperature T = Saturated Temperated at Vapor Pressure
Partial Pressure = (mole fraction) x (Mixture Pressure)
3. The Attempt at a Solution
The dew point temperature is only dependent on the pressure of...
1. Homework Statement
Only Number 1, not number 2
2. Homework Equations
Dew Point Temperature T = Saturated Temperated at Vapor Pressure
Partial Pressure = (mole fraction) x (Mixture Pressure)
3. The Attempt at a Solution
The dew point temperature is only dependent on the pressure of...