Recent content by Reprisal35

Awesome! Thanks again!

Well that makes sense now. v_{avg} = \frac{v_0 + v_f}{2}\\ v_{avg} = \frac{0 + 8.386∗10^7}{2}\\ v_{avg} = 4.193*10^7\\ t = \frac{0.05}{4.193*10^7}\\ t = 1.192*10^{-9}s I feel kinda silly for forgetting to take the avg of speed... Thanks for pointing that out! So both methods give the same...

Sure, d = 0.05m\\ v = 8.386∗10^7\frac{m}{s}\\ v = \frac{d}{t}\\ t = \frac{d}{v}\\ t = \frac{0.05m}{8.386∗10^7\frac{m}{s}}\\ t = 5.96*10^{-10}s

Homework Statement In a CRT tube, electrons are accelerated by a 20,000 V potential difference between the electron gun (the cathode) and the positive metal mesh 5.00 cm away. a. What is the electron’s speed when it reaches the positive wire mesh? b. How much time does it take the electron to...

I think I'll use a variation of what I said and your second argument, thanks again!

Man, I can't believe I was wrong for both parts, thanks for showing me my mistakes and the correct method of solving this. I can prove that part b is infinite along the y and z-axis by using a graph + a demonstration I just found on wolfram. In order to prove that part a is impossible, should...

It should be the same as the y-axis if I'm picturing this correctly. It's as if there's a huge piece of paper that is stretching for infinity along the y and z-axis. That piece of paper represents the locations where the electric potential is zero.

So the position where the electric potential is equal to zero is the vertical line at the point where x=0cm if q1=-5cm and q2=5cm?

Normally, I would say they are 5cm around the original charge, but that's based off of the question giving us a set charge located a fixed distance from a given point and asking us where to place the second charge to create an electric potential of zero. This question gives us two charges and...

Wow, it feels like the weight of my shoulder is gone now. Is there way I can express this in a formula, or it just based off of observation since the charges are equal but of opposite signs? This kinda makes me wonder if the rest of the work I did for part b is also wrong. I want to say that...

Honestly, it just seems impossible for the fields from the two charges to have the same magnitude and opposite directions anywhere in region I or region III when the charges have the same magnitude because the magnitude isn't strong enough to go beyond the other charge. So either there's no...

Wouldn't the magnitude of both the fields be the same but have opposite vectors in order to cancel two fields? This is possible in region I based on an example we did in class, but the example was of two charges with the value of 1nC and -2nC. I just can't seem to make the same connection with...

I forgot that they were opposite signs. What is now throwing me off is that since they are the same charge, but opposite sign, will there be two points, one in region I, and one in region III in which the electric field will be zero? Assuming this, the points where the electric field will be...

Homework Statement A -1.0 nC charge and a 1.0 nC charge are separated by 10.0 cm. a) At what position(s) is the electric field due to the two charges zero? b) At what position(s) is the electric potential due to the two charges zero? c) Draw a graph showing the zero electric field and zero...