Recent content by revere21

In addition, two conceptual questions are asked of the problem. (1) Why is the work done on the block by the normal force zero? I believe this would be because the normal force of the block is equal to the weight, but I am not sure. (2) Imagine the string is now released. The block...

Homework Statement A block of mass 1.60 kg is pulled up a rough 30 degree incline at constant speed by a string parallel to the surface. The friction force on the block is 7.00 N. The incline is 4.00 m long and 2.00 m high. (1) How much gravitational potential energy did the block gain...

Awesome. Thank you, yet again. You, sir, are a freshman-level physics wizard.

So, I take the horizontal component of 129.9 N, and the net horizontal force of 48 N, and plug it into F - f = ma? Is that right? That would give me 129.9 - f = 48, which comes out to f = 81.9 N. Can you give me one final hint and tell me if that is the right way to finish out this problem?

The horizontal component would be 129.9 N, I believe. From using cos30 = adjacent/150. As far as a net horizontal force, where does this come from? Is it just Fhorizontal = 60*0.80 = 48?

Homework Statement A 60 kg box is dragged along a rough but level floor by a rope at a 30o angle to the horizontal. The tension in the rope is 150 N, and the box is speeding up at 0.80 m/s2 (along the floor). (a) How large is the frictional force of the floor on the box? Homework...

Oh my goodness, thank you. Can't believe I didn't catch that one. Very, very simple problem, as it turns out. Thanks, SammyS. Awesome resource to have when my mind is fried from studying.

Okay, so the acceleration of gravity is 9.8 m/s2, which means that gravity causes an object to fall 9.8 meters per second, per second. Am I understanding the gist (sp?) of the point you are trying to convey? Still, in 3 seconds the gravity would have the object moving 3*9.8 = 29.4 m/s, which...

Yes, I understand that x(t) means x is a function of t. I didn't multiply the two together. My apologies for being unclear on that. But to answer your question, the velocity in the x-direction remains constant at 4.00 m/s throughout. So, for every second that passes the diver moves...

Homework Statement A cliff diver runs horizontally at 4.00 m/s. He hits the water 3.00 s later. Ignore air resistance. (a) What is the diver's speed (magnitude of the velocity vector) just before he hits the water? Homework Equations Change in y-component: y(t) = v[SIZE="1"]yot + (1/2)g(t^2)...