I get m=+-sqrt(-4)
=+-2i
y = exp(alpha*x){Acos(beta*x)+Bcos(beta*x)}
where alpha is real and beta is imaginary
therefore
alpha is = 0
beta is = 2
y = Acos(2x)+Bsin(2x)
I put it into the normal version of the self adjoint form.
Where d/dx{p(x)dy/dx}+q(x)y=0
t = integral of 1/p(x) = x^3/3
dt/dx = x^2
dy/dx = dy/dt.dt/dx = dy/dt.x^2
etc.
Then solved using the auxiliary equation. It probably is my working that is wrong, however the question I...
I have got a general solution for the equation
xy'' - y' + 4x^3y = 0, x > 0
by converting to the normal version of the self adjoint form and solving with an auxiliary equation I have
y = Acos(2x) + Bsin(2x)
It then asks to select two independent solutions and verify the wronskian...
The epsilon delta rule states
\epsilon_{ijk}\epsilon_{pqk}=\delta_{ip}\delta_{jq}-\delta_{iq}\delta_{jp}
I am constantly using this but get stuck when it is applied.
For example
\epsilon_{ijk}\epsilon_{pqk}A_{j}B_{l}C_{m}=(\delta_{ip}\delta_{jq}-\delta_{iq}\delta_{jp})A_{j}B_{l}C_{m}...
That can't be true. I have a car stopping with kinetic friction as u*m*g = 0.7 * 1000 * 9.8 = 6860N
I thought static (ABS) is more effective than kinetic
Static coefficient * force = 0.5 * 422 = 211N
This can't be right
I have a specification for a brake caliper that states its clamping force is equal to 4136kg. I know force doesn't equal 4136 but what does clamping force mean then
If a brake caliper exerts 1000kg on a brake pad what is the force due to the this weight?
It can't be umg because there is no g in horizontal weight.
Does g = 1
Therefore F = m
Can anybody shed some light on anti-lock braking systems?
I currently have a model that calculates a vehicle stopping using kinetic sliding friction i.e. it skids to a stop with coefficient of friction at around 0.7 asphalt/tyre or tire which ever you prefer
ABS I believe maintains static...
brilliant you guys are the masters! That was what I was looking for thank.
If you have time could you take look a section of my report deriving drag and tell me what you think?