Recent content by rm_girl

Thanks

Ultraviolet would have the shortest

So would it be near-infrared because it has the longest wavelength, therefore less diffraction?

shorter wavelengths get diffracted at greater angles?

Homework Statement A lens is designed to work in the visible, near-infrared, and near-ultraviolet. The best resolution of this lens from a diffraction standpoint is Options: a.) the same for all wavelengths. b.) in the near-ultraviolet. c.) indeterminate. d.) in the near-infrared. e.)...

Homework Statement Two point charges q1 and q2 are held 4.00cm apart. An electron released at a point that is equidistant from both charges, undergoes an initial acceleration of 8.05×1018m/s2 directly upward in the figure, parallel to the line connecting q1 and q2. Homework Equations...

Homework Statement So a hot wheel was put on a linear track, and one end of the track is slowly lifted until the cart starts to move. The height of the one end is measured as 6.45cm and distance (or hypotenuse) is 189.5cm mass of hot wheel is 45.7 g Homework Equations PE = mgh KE =...

No, we never had to use that equation. But I was just able to derive it using the equation I gave above. Thanks :smile:

which would be? the only equation I know that involves distance and acceleration is d = vot + 1/2at2 which has two unknowns in the equation.

How would I find acceleration from the distance?

Just to make sure, before I start typing up my report. If were to find the acceleration from the equation a = vf-vi/Δt Then I plug that into the F=ma since frictional force is Ff = ukmg I would set ma = ukmg and find uk that way ?

No I didn't get that time. I didn't set up the track and photogate, my lab partner did. And I very much highly doubt he remembers either. I think my professor will accept if I explain it in my lab report what variables I'm missing, then it should be fine.

That's what I figured. Well, I can't go back and do the experiment again. So guess I'm screwed. Thanks for the help though.

Unfortunately we didn't measure the distance between the photogates either. I only thought of getting the time/distance between the photogates AFTER the lab was done. :frown: But I talked to my professor and apparently we can get the acceleration just from those two instantaneous velocity...

Homework Statement For our lab we had to find the coefficient of kinetic friction for a cart on a linear track. We pushed the cart on the track and it went through two photogates which measured the time it spent in the photogate. So through the 1st photogate = 0.0040s 2nd photogate = 0.0062s...