Electric field - Finding the charges

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rm_girl
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Homework Statement


Two point charges q1 and q2 are held 4.00cm apart. An electron released at a point that is equidistant from both charges, undergoes an initial acceleration of 8.05×1018m/s2 directly upward in the figure, parallel to the line connecting q1 and q2.

Diagram of an electron e on the left with an upward acceleration arrow a, 3.00 cm horizontally from a vertical dashed line joining charges q1 (top) and q2 (bottom), separated by 4.00 cm.


Homework Equations


E=k(q/r2)
F=k(q/r2)
E=F/q


The Attempt at a Solution


I already know what the answers are.
q1 = 5.97x10-6 C
q2 = -5.97x10-6 C

I just have no idea how they got those answers. Could someone please explain?
 
rm_girl said:

Homework Statement


Two point charges q1 and q2 are held 4.00cm apart. An electron released at a point that is equidistant from both charges, undergoes an initial acceleration of 8.05×1018m/s2 directly upward in the figure, parallel to the line connecting q1 and q2.

Diagram of an electron e on the left with acceleration arrow a pointing up, a horizontal dashed line of 3.00 cm to a point, and vertical dashed lines of 4.00 cm to charges q1 above and q2 below.


Homework Equations


E=k(q/r2)
F=k(q/r2)
E=F/q



The Attempt at a Solution


I already know what the answers are.
q1 = 5.97x10-6 C
q2 = -5.97x10-6 C

I just have no idea how they got those answers. Could someone please explain?


Both charges exert some force on the electron. Draw the force vectors. What can you say about their direction?

ehild