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Electric field - Finding the charges

  1. Feb 1, 2013 #1
    1. The problem statement, all variables and given/known data
    Two point charges q1 and q2 are held 4.00cm apart. An electron released at a point that is equidistant from both charges, undergoes an initial acceleration of 8.05×1018m/s2 directly upward in the figure, parallel to the line connecting q1 and q2.

    bhgg7a.png

    2. Relevant equations
    E=k(q/r2)
    F=k(q/r2)
    E=F/q


    3. The attempt at a solution
    I already know what the answers are.
    q1 = 5.97x10-6 C
    q2 = -5.97x10-6 C

    I just have no idea how they got those answers. Could someone please explain?
     
  2. jcsd
  3. Feb 1, 2013 #2

    ehild

    User Avatar
    Homework Helper
    Gold Member


    Both charges exert some force on the electron. Draw the force vectors. What can you say about their direction?

    ehild
     
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