Recent content by Robert Houdart

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    68068 as difference of two squares

    i I guess you are right. (a, b) and (b, a) are repeated in my solution, taking pair (a,b) and (b,a) as a single pair yields 8 as the answer.
  2. R

    68068 as difference of two squares

    Homework Statement In how many ways can 68068 be written as the difference of two squares?Homework EquationsThe Attempt at a Solution Let (x+a) * (x+a) -x*x =68068=2*2*7*11*13*17 a (2x+a) =2*2*7*11*13*17 As 2x+a is odd ⇒ a is even ∴a=2b 2b (2x+2b) =2*2*7*11*13*17 b (x+b) =7*11*13*17 x=...
  3. R

    How many ways can 6 cards be chosen from a deck to have all suits present?

    Let us take suits as A, B, C, D Now the different case which arises are 3 A 1 B 1 C 1D 1 A 3 B 1 C 1D 1 A 1 B 3C 1D 1 A 1 B 1C, 3 D 2 A 2 B 1C, 1D 2 A 1 B 2C 1D 2 A 1 B 1C 2 D 1 A 2 B 2C 1D 1 A 2 B 1C 2 D 1 A 1 B 2C 2 D Therefore required number of ways will be 13*13*13 (4* 13c3) + 13*13*6...
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    How many ways can 6 cards be chosen from a deck to have all suits present?

    Homework Statement In how many ways can one choose 6 cards from a normal deck of cards so as to have all suits present?Homework EquationsThe Attempt at a Solution 4 different cards can be chosen in 13*13*13*13 ways. Now we have to choose 2 remaining cards from 48 cards. This can be done in...
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    Question about arithmetic progressions

    Yes, if d=0 is considered, nine more numbers are added to the solution set (1111 , 2222..., 9999) However, my question is, a series (x, x, x, x, x, x, x) be considered an AP (that is can an AP have common difference=0)
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    Question about arithmetic progressions

    Homework Statement Of a 4 digit positive integer, the four digits form an Arithmetic progression from left to right. How many such 4 digit integers exist? 2. The attempt at a solution If d = 1, the integers are 1234, 2345, …, 6789. These 6 integers and their reverses satisfy the given...
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    How Many Non-Confusing Codes Can Be Formed from Distinct Digits?

    (16,61) (18,81) (19,91) (68 ,86) (89, 98) i think these are all (actually total number of numbers were 81 instead of 90 (digits must be distinct)
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    How Many Non-Confusing Codes Can Be Formed from Distinct Digits?

    well , considering 69 and 96 total number pertains to 10
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    How Many Non-Confusing Codes Can Be Formed from Distinct Digits?

    Mod note: This post was a response in a separate cross-posted thread.Ok, I think I got it. Since they are distinct numbers, the first digit can be chosen in 9 ways (except 0) while the second can also be chosen in 9 ways, making it 81 numbers instead of 90.. So am I right this time?
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    How Many Non-Confusing Codes Can Be Formed from Distinct Digits?

    Homework Statement An intelligence agency forms a code of two distinct digits selected from 0, 1 , 2…, 9, such that the first digit of the code is nonzero. The code, handwritten on a slip, can, however, potentially create confusion when read upside down - for example; the code 91 may appear as...
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