Or do you integrate it between radius 3 and 9 with dielectric constant 8 and then integrate it between 9 and 10 with dielectric 1.5?? then how do these two equations combine?? thanks for all the help by the way
Ok so I am guessing that the V equation isn't the right equation then because there are two different dielectric regions. Or is there a way of calculating an overall dielectric constant??
Ok wondering if this is right or even heading in the right direction.
E=Electric field strength
E= q/2*pi*epslion*L
For the two different dielectric domains, 1: r=3mm epsilon=7.08*10^-11 2: r=9mm epsilon=1.33*10^-11
V=Potential difference
V=(-q/2*pi*epsilon*L)(ln10/3)...
Homework Statement
A coaxial cable has an inner core diameter 6mm and inner diameter of the outer sheath is 20mm. There are two layers of insulation between the conductors, the inner layer from a radius of 3mm to 9mm has relative permittivity of 8 while the outer layer from radius 9mm to...
Ok here's my new attempt right or wrong??
Relevant Equations:
magnetic dipole moment mu=NIA
N=number of turns
I=current
A=area
B=magnetic field= (mu_0)(n)(I)
mu_0=magnetic constant
n=turns density
I=current
Attempt:
mu =(25)(2)(7.07x10^-4)
mu= 0.03535...
That is where I am stuck, I know a formula for B is F=BILsin theta but I don't see how this would work? This is the full question but I've no idea how to get the answer.
Homework Statement
Question:
A solenoid has of radius 100mm and turns density of 5 turns/mm has a current of 10 Amps flowing in it. There is a loop of radius 15mm and 25 turns within the solenoid. The loop is free to rotate about an axis which is normal to the axis of the solenoid...