Recent content by rocketgirl93

I didnt know what g for the moon was but I remembered reading somewhere that it is about one sixth of the Earth's g (9.81) so i calculated this figure and guessed Of Gravitation, I posted that in my original solution I do have G: 6.67x10^-11 radius of the moon + distance between...

Hi! Would it pull at you at about 1.64 m/s2? Or at 1.64 x mass?

I take Physics, I'm not afraid to work! It makes it difficult because you don't know what you have to find first and how they want you to approach the questions. I've found these; Orbital radius for the Moon: 3.84 x108m Mass of the Moon: 7.35 x1022kg Actual Radius of the Earth: 6400km

Thanks for the hint! Ok, I'll try find some more, its from this horrific textbook where they don't give you all the constants/data you need at the start of the questions and its scattered throughout the chapter.

Homework Statement There is a point on the line between the centres of the Earth and the moon where their gravitational fields have equal magnitude but are in opposite directions, effectively creating a point of zero gravity. Calculate the distance of this point from the centre of the earth...

Well all good in the sense that I have tried as hard as I possibly can with this question, and am now just accepting that my answer doesn't match up with the one it supposedly is! thank you :)

Ohhh ok and I started parallel to the field ohh ok. Gosh this question is driving me mad. Thank you for all your help though!

I tried to draw my own

I tried doing it again but so far all my triangles still tell me to do sin60... and using the diameter of the circle didnt work

Great! Thank you!

Yes, would you do diameter x cos60?

sinx = O/H But then do you have to find the diameter of the loop to act as the hypotenuse?

Would you use trig to find the perpendicular component?

I'm sorry, I don't know

Yay! Thank you so much for your help!