Recent content by rosedog09
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Drag Forces and Terminal Velocity
All good. I can relate atm. All my AP exams are coming up and that doesn't stop my teachers from assigning lots of homework, so lots of late nights.- rosedog09
- Post #6
- Forum: Introductory Physics Homework Help
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Drag Forces and Terminal Velocity
Teacher says Im wrong on both these questions. I have consulted with other teachers and they say im correct. What do you guys think? 3. As mass increases, so does terminal velocity. 5. Fnet = FDrag - Fg ma = FDrag - mg FDrag = 79(8) + 79(10) FDrag = 632 + 790 = 1422 N Teacher Comments 5...- rosedog09
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- Mass Velocity
- Replies: 8
- Forum: Introductory Physics Homework Help
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Blowing Into Your Own Sail
This makes sense. I didnt think about the timing of it.- rosedog09
- Post #25
- Forum: Introductory Physics Homework Help
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Blowing Into Your Own Sail
Ok I think I am having trouble because I keep bouncing between force, momentum energy, etc The fan "adds" (yes I know its a conversion) energy to the system, so Energy final =/= Energy Initial within the system. Since the objects of momentum come from outside the system (air) momentum is not...- rosedog09
- Post #23
- Forum: Introductory Physics Homework Help
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Blowing Into Your Own Sail
I dont know. It bothers me, but I dont know.- rosedog09
- Post #20
- Forum: Introductory Physics Homework Help
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Blowing Into Your Own Sail
Ok. I think I've figured it out. The sail is reflecting the air (in this case with an unrealistic level of efficiency) such that momentum goes from p to -p, a total change of -2p. Since the fan initially transferred p to the air we are left with -p, so it is essentially the same as having the...- rosedog09
- Post #18
- Forum: Introductory Physics Homework Help
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Blowing Into Your Own Sail
Ok so what your suggesting is that the momentum change (impulse) on the sail is greater than the fan because the particle is reversing directions. I can understand this, but I still find it hard to understand how there is enough momentum from the fan for it to transfer more momentum to the sail...- rosedog09
- Post #16
- Forum: Introductory Physics Homework Help
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Blowing Into Your Own Sail
Ok I can see that this works, but I want to understand why. I am not understanding how the air could possibly enact a greater change in momentum on the cart after bouncing back than it did when it hit the blade of the fan (pushing the cart backwards) initially.- rosedog09
- Post #7
- Forum: Introductory Physics Homework Help
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Blowing Into Your Own Sail
I understand that the sail will enact a forward force on the cart due to newtons third law from bouncing the air back, but I dont understand why this force would not be counteracted by the force which air exerts on the fan (Newtons third law).- rosedog09
- Post #6
- Forum: Introductory Physics Homework Help
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Hello - A drowning student taking AP Physics 1 Online
Thank you for the helpful information. Judging by your profile and signature Im guessing your a ham radio operator. I got my technician license about a year ago, but Ive been too busy to get my radio properly setup and use it. Anyways thats really cool :) See you around.- rosedog09
- Post #4
- Forum: New Member Introductions
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Blowing Into Your Own Sail
C. There is no net change in force, momentum, or velocity of the sail craft because the fan exerts a forward force on the air; however due to Newton's third law the air exerts an equal and opposite force on the fan. This air then exerts a forward force on the sail which cancels out the rearward...- rosedog09
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- Force Momentum Newton's third law
- Replies: 25
- Forum: Introductory Physics Homework Help
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Torque on a Pivot Point With Multiple Forces and Different Directions
Isn't force 3 to the left of the pivot point? My bigger issue is I don't understand why I am not getting credit for question 8.- rosedog09
- Post #5
- Forum: Introductory Physics Homework Help
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Torque on a Pivot Point With Multiple Forces and Different Directions
7. Ok, I see my mistake, that would make the equation -100(1)-50(.5)+50(.75) = - 87.5 8. If that is correct, what principle or equation could I show to prove my work to my teacher?- rosedog09
- Post #3
- Forum: Introductory Physics Homework Help
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Torque on a Pivot Point With Multiple Forces and Different Directions
My AP Physics notes state that counterclockwise is generally positive and clockwise is generally negative. This makes sense to me and means forces on opposite sides of the pivot point which act in opposite directions will work together, and this is the logic I applied to answer the problems...- rosedog09
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- Forces Pivot Torque
- Replies: 6
- Forum: Introductory Physics Homework Help