Hello again, tonite I am working on more homework and I am stuck on a problem involving circular motion. Here's the question:
Q: A 24 kg child takes a ride on a fast Ferris wheel that rotates 4.5 times each minute and has a diameter of 19 m. (a) What is the centripetal acceleration of the...
Well, I'm just wondering on this one...but isn't the T of the string that is holding the block on the incline equal to the T of the string holding the hanging block?
So how would you figure out T on the hanging block?
Oh wow, I can't believe I didnt see that, I had it almost written like that except I dint have ma on the other side, in which case i would have no way to cancel the mass.
Thanks much both Chi and Astro!
If you want more, there is a decent wikipedia entry on the http://en.wikipedia.org/wiki/Friction_coefficient#Coefficient_of_friction" that you might want to check out.
Basically, the value "mu" is a constant (depending on the surfaces) that shows the ratio of the force of friction and the force...
Oh, and there's an update...I got the second problem by not dividing the force in the y direction by two. It was a pure guess and check, so if someone can explain why that would be greatly appreciated.
F=ma
Ok, I was trying to use that but don't we have two unknowns here?
We don't know m, and we can't get the F[SIZE="1"]F=(mu)F[SIZE="1"]N
So how can I use the Force of friction on the tires if I have no mass and only acceleration?
Because we are using an adjacent leg and the hypoenuse, so according to my favorite math acronym...or whatever its called:
SOHCAHTOA
We are using A and H so we would use cos.
Well since the line is 34 degrees north of west, I believe you would have to look at the line like this ___[SIZE="1"]34_\________ so you would have to figure out the supplementary angle, and that would be angle ABC
Well I want to know if natarae might have made a mistake in his equation to figure out AC
they wrote:
But I think the AC^2 and the AC are meant to be BC^2 and BC respectively, which would make it possible to find AC.
AC was what you figured out in part A.
And to figure out angle ABC you could draw a straight line with another line coming off of it at a 34 degree angle. So what do you get for angle ABC? What you get for that you can plug into the equations that natarae gave you because then you'll have...
Hello everyone, I'm sorry if a question like this has been posted before, but I am trying to get my online work done for tonight and I have come across two problems that I just can't get past. I have gotten far into the problems but the website I enter values in on says theyre wrong. I...