Recent content by rsala

Homework Statement Pluto's diameter is approximately 2370 km, and the diameter of its satellite Charon is 1250 km Although the distance varies, they are often about 1.99×104 km apart, center-to-center. Assuming that both Pluto and Charon have the same composition and hence the same average...

since it is at rest, and static frictional force varies, the weight downwards only the inclined plane equals the frictional force, and will remain to equal it, until the maximum static friction is reached then it jerks loose

i wrote 333.333 on the test now i don't know what to say, whether it got it wrong or not

I see i made the mistake, the velocity of the block initially should be .98 m/s NOT 3.13 ic the wrong bullet momen. now, it is 3 so should the final velocity of the bullet be 333.3333 m/s? or is it 327, ? thank you

Homework Statement a ballistic pendulum is hit by a bullet traveling 500m/s , the ballistic pendulum is a block of wood hanging from a string. the block of wood (1kg) is hanging from the string of 2.5m the bullet has mass .006kg @ 500m/s the bullet passes right through the block of wood...

wow that was simple, hm well the next part of the problem asks to find the k constant if she jumps and JUST reachs the water,, is the energy approach, then correct? BTW how did you know to set the forces equal to each other and not the energys? thanks

Homework Statement Kate, a bungee jumper, wants to jump off the edge of a bridge that spans a river below. Kate has a mass m, and the surface of the bridge is a height h above the water. The bungee cord, which has length L when unstretched, will first straighten and then stretch as Kate falls...

Homework Statement A wooden rod of negligible mass and length 85.0 is pivoted about a horizontal axis through its center. A white rat with mass 0.500 clings to one end of the stick, and a mouse with mass 0.240 clings to the other end. The system is released from rest with the rod...

i understand now, answer is 5r/2 thanks doc al

i don't understand. can you explain?

also i tried the answer 2R, since energy should be conserved,, and it should make it back up the distance it went down,, i think. didnt work

Homework Statement problem should be solved somewhat with energy conservation. A car in an amusement park ride rolls without friction around the track shown in the figure . It starts from rest at point A at a height h above the bottom of the loop. Treat the car as a particle. What is the...

4.784 m/s once it leaves muzzle solved now though, i didnt know how to properly set any of the initial and final energies, so i couldn't solve it initially, i got it now though. thanks again

jesus wrong again, i got 22.89166 m/s this time, lol i have used \sqrt{\frac{2(mgh+\frac{1}{2}kx^{2})}{m}} --- \sqrt{\frac{2((1.5)(9.8)(-.25)+\frac{1}{2}(667)(-.25^{2}))}{1.5}} o nvm i forgot the sqrt, i got correct answer now! 4.784 thank you feldoh, kamerling

yes i did, i just tried again with correct negatives i think (i see where i went wrong last time) and i got answer: 3.38m/s, wrong still though mgh + \frac{1}{2}kx^{2} = \frac{1}{2}mv^{2}