ahhh... i knew the hieghts should have been h-h1 and h-h2. i tried that but i donno how u got v1 to equal kv2, i keep on getting v1^2 + g(h-.8)=v2^2 + g(h-3.6)
what am i doing wrong?
.5\rho g h +P = .5\rho v1^2 + \rho g h1 + P + 5\rho v2^2 + \rho g h2 + P
this is the main equation i used to derive the velocities related to the height. but i donno if its in the right set up
these problems suck balls man! i sat here for a good 3 hours trying to figure it out. but no good. man i donno how to type out the work using regular stuff. i which it had symbols on the forum. the source of these problems is my physics book. by james walker.
Homework Statement
The water tank is open to the atmosphere and has two holes in it, one at 0.80m and the other at 3.6m above the floor on which the tank rests. if the two streams of water strike the floor in the same place, what i the depth of water in the tank.
tank height is 5 m...
Homework Statement
Tests of lung capacity show that adults are able to exhale 1.5 liters of air through their mouths in as little as 1.0 seconds. a)if a person blows air at this rate through a drinking straw with a diameter of 0.60 cm, what is the speed of air in the straw? b) if the air from...
the vacuum created by sucking your cheeks in.
i came up with this solution.
P1 + rough (g) (h1) = P2 + rough (g) (h2)
P1=0, h1=0
so P2 = rough (g)(h2)
1 atm= 1000(10)(h2)
1.01 EE5=1.0EE4(h2)
h2= 10 m
but I am not sure.
well i know the answer is 10 m if you round gravity to 10 m/s^2. i also know that the pressure on the top of the straw is 0 Pa. but besides that i have no clue, that's why I am asking it.
As a stunt, you want to sip some water through a very long, vertical straw. what is the tallest straw that you could, in principle, drink from in this way?