Recent content by Rusjar

It's indeed a mobile system. I was hoping for an easy way to calculate the required torque but I know now I still have some work to do. Thanks for the answers though! Experimenting with an electric hand drill is a very good one, haven't thought about that, thanks ;)

No, the belt doesn't move while the systems is going over the rollers. So the weight of the belt is leaning on the system, that's where the 150N comes from.

The check the condition of the bearings in the rolls, by rotating them an ultrasound can be detected.

I want to make a system which rides between the conveyor belt and the rollers underneath. The system is balanced because it is fixed to the conveyor belt, it only leans on the rolls and rotates them.

The hollow cylinder contains 2 bearings on each end and has a shaft going through it. The shaft is fixed on both ends. The 150N is caused by the weight of a system where the two wheels are a part of.

So I can just calculate T = I * a (alfa) for the driving wheel on the right without having to deal with the 150N downwards?

I understand the part of the friction now, thanks! But it's still not clear to me how I can calculate the required torque (for the motor connected to the wheel) so that the roll will rotate with 250 rpm and the wheel will rotate with 415 rpm when a force of 150N pushing downwards on the shaft...

Well if the shaft through the wheel exerts a force of 150N downwards, then there will be a normal force (Fn) at the place where the wheel makes contact with the roll, right? And that normal force multiplied with the friciton coefficient of rubber and steel gives a friction force. Or is this not...

The Fw and Fn forces are coming from the 150N which is pushing down on the roll. These are the reaction forces. I cannot agree with you on that last sentence. If you would push a car, the friction forces on the wheels play a major role in how much force you would need.

I'm sorry, the 0.0042 should be 0.004 0.04^2. The 67.88*0.04 is the moment created by the friction force. That one should be included right? And I calculated the torque for the wheel, and the wheel is not hollow thus should be I = 0.5*m*r^2

The bigger circle is a hollow cylinder (steel) with a length of 0.6m and a diameter of 0.133m and a mass of 8kg. The 2 smaller circles are rubber wheels with a diameter of 0.080 and mass of 0.2kg. Both the roll and the wheels have ball bearings and are mounted on a shaft. On both the shafts of...