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- I want to rotate a roll by using a smaller rubber wheel. In this calculation I'm trying to calculate the torque for the smaller wheel.

The bigger circle is a hollow cylinder (steel) with a length of 0.6m and a diameter of 0.133m and a mass of 8kg. The 2 smaller circles are rubber wheels with a diameter of 0.080 and mass of 0.2kg. Both the roll and the wheels have ball bearings and are mounted on a shaft. On both the shafts of the wheels a force of 150N is pressed down. The shaft of the right wheel is connected directly to a motor.

If I want the roll to accelerate to a speed of 250rpm in 3 seconds, what is the torque required for the driving wheel? I’ve made a calculation myself but I’m not sure if its correct.

I = 0.5*0.2*~~0.0042~~ 0.04^2 = 0.00016 kgm2

415 rpm = 43.46 rad/s = ω(3s)

Now: ω(3s) = α * t

43.46 = α * 3

Makes α = 14.49 rad/s2

T = I * α

T – 67.88*0.04 = 0.00016 * 14.49

T = 2.7 Nm

Is this calculation correct? Is there 2.7 Nm of torque required in order for the roll to rotate with 250 rpm in 3 seconds?

If I want the roll to accelerate to a speed of 250rpm in 3 seconds, what is the torque required for the driving wheel? I’ve made a calculation myself but I’m not sure if its correct.

I = 0.5*0.2*

415 rpm = 43.46 rad/s = ω(3s)

Now: ω(3s) = α * t

43.46 = α * 3

Makes α = 14.49 rad/s2

T = I * α

T – 67.88*0.04 = 0.00016 * 14.49

T = 2.7 Nm

Is this calculation correct? Is there 2.7 Nm of torque required in order for the roll to rotate with 250 rpm in 3 seconds?

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