- #1
Rusjar
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The bigger circle is a hollow cylinder (steel) with a length of 0.6m and a diameter of 0.133m and a mass of 8kg. The 2 smaller circles are rubber wheels with a diameter of 0.080 and mass of 0.2kg. Both the roll and the wheels have ball bearings and are mounted on a shaft. On both the shafts of the wheels a force of 150N is pressed down. The shaft of the right wheel is connected directly to a motor.
If I want the roll to accelerate to a speed of 250rpm in 3 seconds, what is the torque required for the driving wheel? I’ve made a calculation myself but I’m not sure if its correct.
I = 0.5*0.2*0.0042 0.04^2 = 0.00016 kgm2
415 rpm = 43.46 rad/s = ω(3s)
Now: ω(3s) = α * t
43.46 = α * 3
Makes α = 14.49 rad/s2
T = I * α
T – 67.88*0.04 = 0.00016 * 14.49
T = 2.7 Nm
Is this calculation correct? Is there 2.7 Nm of torque required in order for the roll to rotate with 250 rpm in 3 seconds?
If I want the roll to accelerate to a speed of 250rpm in 3 seconds, what is the torque required for the driving wheel? I’ve made a calculation myself but I’m not sure if its correct.
I = 0.5*0.2*
415 rpm = 43.46 rad/s = ω(3s)
Now: ω(3s) = α * t
43.46 = α * 3
Makes α = 14.49 rad/s2
T = I * α
T – 67.88*0.04 = 0.00016 * 14.49
T = 2.7 Nm
Is this calculation correct? Is there 2.7 Nm of torque required in order for the roll to rotate with 250 rpm in 3 seconds?
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