Recent content by Sarah Hallsway

Oh, it would be 0, right? When I use 0 for theta0 in snell's law, I get that theta1 also equals 0, and when I put that into the equation m(lambda)=d(sin(theta1)+sin(theta2)), I get an extremely small value for the first order diffraction angle (theta2). Where am I going wrong? Also, is the...

Homework Statement Light of wavelength 600 nm passes through two slits separated by 0.20 mm and is observed on a screen 1.0 m behind the slits. The location of the central maximum is marked on the screen and labeled y=0. (I only need help on the last 2 parts, but I will list all of them in...

Homework Statement A 600 line/mm diffraction grating is in an empty aquarium tank. The index of refraction of the glass walls is [n][/glass] = 1.50. A helium-neon laser (lambda=633 nm) is outside the aquarium. The laser beam passes through the glass wall and illuminates the diffraction grating...