Recent content by Sat-P

  1. Sat-P

    Electromagnetic force on a positively charged particle

    Magnitude of the net force acting on the charged particle due to both fields
  2. Sat-P

    Electromagnetic force on a positively charged particle

  3. Sat-P

    Chemistry Oxidation of alkene followed by Cu, heat

    The answer I am getting is A but the answer given is D. I don't know why D because this is what I did. First I opened the alkene and then added OH on the less substituted carbon( Markonikov addition) and we know that Cu, Heat turns 3° alcohol to alkene so then I got an alkene. Did I do something...
  4. Sat-P

    Equivalent resistance of this 6-sided circuit

    After solving this one I got 11R/20 so is it the answer, did I do it right
  5. Sat-P

    Equivalent resistance of this 6-sided circuit

    Oh, I just saw the mistake. Let me do it again
  6. Sat-P

    Equivalent resistance of this 6-sided circuit

    Sir, I've tried both the methods you gave The answers I am getting are different, please check is there something I did wrong or misinterpreted what you said
  7. Sat-P

    Equivalent resistance of this 6-sided circuit

    Even after I split the node 0ab , the other radial resistors are causing me trouble, if I can get a way to simplify them then it will be all good
  8. Sat-P

    Equivalent resistance of this 6-sided circuit

    Got it
  9. Sat-P

    Equivalent resistance of this 6-sided circuit

    How can you say that the current through ab is 2 Ampere
  10. Sat-P

    Equivalent resistance of this 6-sided circuit

    Can you please clarify why the current through the resistors connected to a should not be equal?
  11. Sat-P

    Solve ##x^{\frac{-1}{2}}-2x^{\frac{1}{2}}+x^{\frac{2}{3}}=0##

    What you are saying is indeed true and if we follow the general trend there might or might not be 7 solutions to that equation which can't be solved using basic algebra.
  12. Sat-P

    Solve ##x^{\frac{-1}{2}}-2x^{\frac{1}{2}}+x^{\frac{2}{3}}=0##

    It can be easily deducted from the question.
  13. Sat-P

    Solve ##x^{\frac{-1}{2}}-2x^{\frac{1}{2}}+x^{\frac{2}{3}}=0##

    Sir, this is indeed basic algebra for us. Maybe they don't teach this in high school
  14. Sat-P

    Equivalent resistance of this 6-sided circuit

    I am sorry for the misinterpretation, but the current through resistor 0b will be more i.e 0.65 i (approx) and current through resistor a0 is 0.334 I (approx). You can see the results in the image above. I've edited the above post.
  15. Sat-P

    Equivalent resistance of this 6-sided circuit

    Earlier, I thought that current through resistor a0 and 0b will be the same but I was wrong, when I interpreted this mathematically I got that the current through the resistor 0b will be more than that through the resistor a0, and then I thought that current through f0 and c0 might be mirror...
Back
Top