Equivalent resistance of this 6-sided circuit

[haruspex]

Got it

So can you solve it now using the splitting up of node 0?

 

[Sat-P]

Even after I split the node 0ab , the other radial resistors are causing me trouble, if I can get a way to simplify them then it will be all good

 

[haruspex]

Even after I split the node 0ab , the other radial resistors are causing me trouble, if I can get a way to simplify them then it will be all good

In post #32 you recognised (guessed?) that, by symmetry, the current along 2-0 is the same as along 0-5. That allows you to split $0_{2345}$ into two nodes, $0_{25}, 0_{34}$.

 

[BvU]

Once you understand the consequences of the dashed red symmetry line, you can work from right to left.

$\$

 

[Sat-P]

Sir, I've tried both the methods you gave
The answers I am getting are different, please check is there something I did wrong or misinterpreted what you said

 

[BvU]

What are we looking at ? (with a pain from craning our neck) ?
I can distinguish you replace the rightmost three with ${2\over 3} R$, so the rightmost five give ${8\over 3} R$. OK.

But why $R/2$ ?

$\$

 

[Sat-P]

Oh, I just saw the mistake. Let me do it again

 

[Sat-P]

After solving this one I got 11R/20 so is it the answer, did I do it right

 

[DaveE]

After solving this one I got 11R/20 so is it the answer, did I do it right

Agrees with mine, but I didn't double check.

Checking your own work is a key skill in the physical sciences. Out in the real world they don't want to pay 2 people to do one job, and they don't want to pay one person to do the job incorrectly.

 

[BvU]

After solving this one I got 11R/20 so is it the answer, did I do it right

The answer isn't really the important element. Whther you did it right can only be confirmed if you post your work.

Free tip: work it out neatly ...