Recent content by Sbr:132

I know the definition but I want to know why?

] I found in a textbook that the value does not change because the centripetal force is perpendicular to the tangential velocity. But I am confused, because a vector can have a component, which is perpendicular to the vector. So if the centripetal force is perpendicular to the tangential...

look you almost 40 yrs elder than me. if my sum below is worng do the right sum for me mathematically and prove that there will be a collision.I'm just a college student.and I want to understand it. my sum is below Firtly we need to find how much time sue's car take to stop V=u+at 0=30+(-2*t)...

Firtly we need to find how much time sue's car take to stop V=u+at 0=30+(-2*t) -30=-2t t=15 and after acclerating at -2ms-2 sues car will stop after 15 s and the distance the car will reach S=ut+1/2at2=30*15+1/2*(-2)*(15)2=225m in that 15 sec how much the slow van will go s=vt=15*5=75 and after...

[Q..UOTE="haruspex, post: 5258893, member: 334404"]This approach will not work. Indeed, you got the wrong answer. They collide before Sue comes to a stop. Ok. please do the right answer for me. your working approach.

Firtly we need to find how much time sue's car take to stop V=u+at 0=30+(-2*t) -30=-2t t=15 in that 15 sec how much the slow van will go s=vt=15*5=75 and after acclerating at -2ms-2 sues car will stop after 15 s and the distance the car will reach S=ut+1/2at2=30*15+1/2*(-2)*(15)2=225m in that 15...

There will be No collision.and the distance between them will be 5 m.

Thanks

Hey, I am SBR,a physics freak.Physcis is my everything.That's all.