Recent content by schoolboy10

LaTeX Code: C_e V_e + C_w V_w =m LaTeX Code: C_e V_e + C_w V_w = 1 LaTeX Code: (1/100)(100) + (x/100)(100) = 1 1+ 100x/100 = 1 1+ x = 1 x= 0 This would be the initial amount in ether, correct? Arghh I'm still stuck :(

Ok, I think I understand now: k=10 10=g/50mL ether/ 1g/100mL water 10= g/50mL ether .2 = g/mL ether 10=g/100mL ether/ 1g/100mL water .1=g/mL ether So there is more benzoic acid left when using 50mL (small amount) than 100mL (large amount) of ether. Please tell me I did it right lol

Ok well here's where I'm a little confused. I gave the equation of above as: Kdistribution = g/100mL ether layer / g/100mL aqueous layer So am I wrong in saying that all of the sample is in the aqueous layer at first and none in the ether layer? So it would be 0g/100mL in the numerator and...

k = 50mL / 100 mL = .5 k= 100/100 = 1 Isn't this what I did orginally?

I'm guessing benzoic acid is more soluble in dimethyl ether than water, but in water more than dioxane?

You're really smart Borek, lol. Assume there is 0.5 g of benzoic acid that needs to be extracted. Then: .5g/100mL = 0.005g/mL & .5g/50mL = 0.01g/mL -> x2 extractions = 0.02g/mL Now I'm stuck, does this mean that there is 0.02g of benzoic acid per mL of water or ether?

Homework Statement Show that using small volumes of ether solvent in an extraction from aqueous phase is better than using larger volumes. The total volume of organic solvent, amount of material to extract, aqueous volume and distribution constant are the same. You can do this with an...

Yeah I'm sorry again guys, I screwed up the question in the beginning by not giving enough info lol. Benzoic acid is originally mixed in ethanol. We then place this in a separatory funnel with water and ether. This is where the question applies. Why can't we use dioxane as the ether to extract...

Sorry, I doubled check and this is not the case. I didn't give enough information in the problem statement, I'm sorry. A solution containing biphenyl and benzoic acid is mixed with water and ether. We originally need to extract both of these compounds into the ether phase which is what the...

Correct.

Homework Statement Why is it possible to use dimethyl ether as a solvent for extraction of benzoic acid and not dioxane? Homework Equations The Attempt at a Solution I'm thinking that it's because dioxane has more of a hydrophobic character since it has many carbons, but then...

Ahh I see, thank you. So after I do the calculations to find the volume, was I right in saying originally that you double the volume since there are two double bonds?

Oh, silly me, it would be 0.08315, correct?

Homework Statement Calculate the volume required to hydrogenate 50g of trans-carveol at STP. Homework Equations PV=nRT m=152g The Attempt at a Solution I think I might have this one but just for clarification if I'm missing something. The amount of moles is 0.329 using the amount...

All three are equivalent. Lewis structures are simple drawings, they don't take into account VSEPR theory.