Yes, P stands for power
I substituted P/v in for my applied force, since power = Force*velocity
I should be allowed to make the sub.
the equations simplified: Force - weight(portion along x axis) - Friction = 0 ... (constant velocity tells me that the equation is in equalibrium)
Energy is conserved;
Eintial = Efinal
Pei + Kei = Pef + Kef
mgh + 1/2mvi^2 = 1/2mvf^2
or from equations of motion:
v^2 = v0^2 + 2*a*x where x is h
both result in the same answer.
This should be an easy question, but I am having problems with my conflicting solutions. Maybe someone could help.
A 1900 kg car experiences a combined force of air resistance and friction that has the same magnitude whether the car goes up or down the hill at 27 m/s. Going up a hill, the...