Recent content by Searay330

It Makes perfect sense to me but the homework program told me i got the wrong answer. is there some mistake in my calculation?

oh it must have 1/C

well that would mean the Amps cancel leaving that as just a number and the only unit left is C which x picks up when its distributed across those numbers. correct

.7145557656 (A/A cancels) = (1 - (32.4xC)) - (32.4xC) = .2854442344 - xC = .2854442344/32.4 x = .0088100072 C

well that's my problem it says my answers units should be C-1 but by using the formula wouldn't the units just be C

so then plugging everything in you would get .378/.529 = (1- x(52.4-20)) meaning x = .0088100072

right so you can changed the formula to be I2/I1 = (1 - TCOR(TF - TI))

how can the resistance be constant if the voltage is constant and the current changes?

Suppose a wire made from an unknown alloy and having a temperature of 20.0°C carries a current of 0.529 A. At 52.4°C the current is 0.378 A for the same potential difference. Find the temperature coefficient of resistivity of the alloy. tempinital = 20C tempfinal = 52.4C currentInital = .529A...

yes

its increased by 2(αLΔT) one for each side

im not sure the change in area would be equal to the new L2 and that is the only dimension that changes

this is a picture of my notes for thermal expansion for linear vs area. my question is why does the area coefficient of expansion for the area = 2(liner coefficient of expansion). any insight would be appreciated.

Right so if the internal energy doesn't change that means that for part c Q = W or 2.5KJ Thank you very much for your help

i am not sure because if it is contact with the heat reservoir that would that mean that temperature doesn't change and it would be 0