Recent content by sebasalekhine7

I have this problem, and I have attepmted a classical approach without much success. A man 5 ft tall runs at a rate of 8ft/sec towards a source of light that arises vertically at a point A. The height of the light source H, is given by the formula h(t)=t^3 +1, in feet, where time t is...

that would mean that y=?

so the solution should just be \frac{dy}{dx}=ky^{-\frac{1}{2}} ?

ok, but why is the "x" in the left side of the equation, why is there an x at all?

why is the x beside the (dy/dx)?

The rate of change of y with respect to x is inversely proportional to the square root of y. a)Write a differential equation for the given statement b)Solve the differential equation in part a. I don't know, but what I've done so far is: ({dy/dx}) k=y^{1/2}

what is \bar{R}_{E} ?

Sorry, but can you explain what the second formula means?

How can I measure altitude depending on the period of a pendulum? I know I have to calculate the value for g but I don't know how exactly altitude could be calculated.

I think they are both equally creative, well, thanks a lot for your help.

Sorry, but I don't quite understand how to do what you just wrote.

I found something very strange working with Riemann sums and expansion series. Can anyone tell me why \frac{x^n}{\sum_{i=1}^n x^{n-i}}=\frac{(x-1)x^n}{x^n-1} Excuse the profanity, but I thought in the beginning this was a disgusting joke! :smile: :confused:

Rewrite done.

Can anyone proove why {x^n} /\sum_{0}^{x}x^{n-1}={x-1}/x

Ok, I think I've got question # 1. Is orbital angular momentum =angular velocity*radius^2 ?