- #1
sebasalekhine7
- 23
- 0
I found something very strange working with Riemann sums and expansion series.
Can anyone tell me why
[tex]\frac{x^n}{\sum_{i=1}^n x^{n-i}}=\frac{(x-1)x^n}{x^n-1}[/tex]
Excuse the profanity, but I thought in the beginning this was a disgusting joke! :rofl: :yuck:
Can anyone tell me why
[tex]\frac{x^n}{\sum_{i=1}^n x^{n-i}}=\frac{(x-1)x^n}{x^n-1}[/tex]
Excuse the profanity, but I thought in the beginning this was a disgusting joke! :rofl: :yuck: