Recent content by SevenHells

I've fixed that now, thanks. Did you have something typed before "Oh,"?

Homework Statement I have a particle moving with uniform velocity in a frame ##S##, with coordinates $$ x^\mu , \mu=0,1,2,3. $$ I need to show that the particle also has uniform velocity in a frame ## S' ##, given by $$x'^\mu=\dfrac{A_\nu^\mu x^\nu + b^\mu}{c_\nu x^\nu + d}, $$ with ##...

I actually meant to ask about the ## \dot{q} ## term in the lagrangian! I can see it's not an exact time derivative because of the ##e^{\gamma t}## term, right?

I have another question. In the first part of the question above, the equation of motion is a damped oscillator $$ \ddot{q} + \gamma \dot{q} - \dfrac{k}{m}q = 0 $$ Why can't I drop the ## \gamma \dot{q} ## term, is it not the time derivative of ##\gamma q##? Thanks

$$2[y(x)][y'(x)]$$ so I guess my "f" would be $$-(\dfrac{\sqrt{m\gamma}}{2} s)^2$$ thanks for that!

Hi WannabeNewton, I have a question I was hoping you could answer. I have a lagrangian $$L=\dfrac{m}{2}e^{\gamma t}\dot{q}^2 - e^{\gamma t}\dfrac{k}{2}q^2 $$ I solve it for the equation of motion and then I use a transformation $$ s=e^{\frac{\gamma t}{2}} $$ and rewrite the original...