Show that a nonlinear transformation preseves velocity

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Homework Help Overview

The problem involves demonstrating that a nonlinear transformation preserves the uniform velocity of a particle moving in a specific frame. The transformation is defined by a set of equations involving constants, and the original poster is exploring how to show that uniform velocity translates across different frames.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to express the coordinates in the new frame and calculate velocities but is uncertain about the correctness of their approach. They seek guidance on how to demonstrate preservation of velocity for the given transformation.

Discussion Status

Some participants have provided hints about working with differentials and using the chain rule to analyze the transformation. There is an acknowledgment of the classic nature of the problem, suggesting that it is well-studied, but no consensus has been reached on the specific steps to take.

Contextual Notes

The original poster notes that "uniform velocity" implies zero acceleration, which is a key aspect of the problem. There is also a mention of the formatting for inline math, indicating a focus on clarity in mathematical expressions.

SevenHells
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Homework Statement


I have a particle moving with uniform velocity in a frame ##S##, with coordinates $$ x^\mu , \mu=0,1,2,3. $$
I need to show that the particle also has uniform velocity in a frame ## S' ##, given by
$$x'^\mu=\dfrac{A_\nu^\mu x^\nu + b^\mu}{c_\nu x^\nu + d}, $$
with ## A_\nu^\mu,b^\mu,c_\nu x^\nu,d ## constant.

Homework Equations


I don't think these are very relevant because they're not the transformations for the question but
$$\Delta x = \gamma(\Delta x' + v\Delta t')$$
$$\Delta t = \gamma(\Delta t' + v\Delta x'/c^2)$$
$$\Delta x' = \gamma(\Delta x - v\Delta t)$$
$$\Delta t' = \gamma(\Delta t - v\Delta x/c^2)$$

The Attempt at a Solution


I wrote the ## S' ## coordinates out and using ## x'^0=t'##,##x'^1=x'##,##x'^2=y'##,##x'^3=z' ##, try to calculate the velocities but I don't think it's right. I'm not sure how to show a transformation preserves the particle velocity. Could anyone point me how to show this for the Lorentz transformations, and then I could try to do it for my transformations?
 
Last edited:
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Oh, and for inline math we use ## \#\# ## to start and end, not ##$##
 
BvU said:
Oh, and for inline math we use ## \#\# ## to start and end, not ##$##
I've fixed that now, thanks. Did you have something typed before "Oh,"?
 
Ummm, no ... :frown:
 
SevenHells said:
I have a particle moving with uniform velocity in a frame ##S##, with coordinates $$ x^\mu , \mu=0,1,2,3. $$
I need to show that the particle also has uniform velocity in a frame ## S' ##, given by
$$x'^\mu=\dfrac{A_\nu^\mu x^\nu + b^\mu}{c_\nu x^\nu + d}, $$
with ## A_\nu^\mu,b^\mu,c_\nu x^\nu,d ## constant.
"Uniform velocity" means zero acceleration. So you must show that if $$\frac{dv^i}{dt} \equiv \frac{d^2 x^i}{dt^2} = 0$$then
$$\frac{dv'^i}{dt'} \equiv\frac{d^2 x'^i}{dt'^2} = 0$$ (where ##i=1,2,3##).

BTW, what is the context of this problem? It's actually a classic -- the fractional linear transformations are known to be the most general transformations which preserve inertial motion. :-)

Not sure how much of a hint I should give you, so I'll start with this:

Work with the differentials, i.e., find ##dx^i## and ##dt## separately, then take their quotient to find an expression for ##v##. Take differential ##dv## similarly, and take its quotient with ##dt## to find the acceleration.

Further hints: use the chain rule to compute the various differentials.
 

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