Show that a nonlinear transformation preseves velocity

AI Thread Summary
To demonstrate that a nonlinear transformation preserves velocity, one must show that a particle moving with uniform velocity in frame S maintains this property in frame S'. The transformation is defined as x'^\mu = (A_\nu^\mu x^\nu + b^\mu) / (c_\nu x^\nu + d), where A_\nu^\mu, b^\mu, c_\nu, and d are constants. The key is to prove that if the acceleration (d^2 x^i/dt^2) is zero in frame S, it remains zero in frame S' (d^2 x'^i/dt'^2 = 0). This involves calculating differentials and applying the chain rule to relate the velocities and accelerations in both frames. The discussion highlights that fractional linear transformations are the most general form preserving inertial motion.
SevenHells
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Homework Statement


I have a particle moving with uniform velocity in a frame ##S##, with coordinates $$ x^\mu , \mu=0,1,2,3. $$
I need to show that the particle also has uniform velocity in a frame ## S' ##, given by
$$x'^\mu=\dfrac{A_\nu^\mu x^\nu + b^\mu}{c_\nu x^\nu + d}, $$
with ## A_\nu^\mu,b^\mu,c_\nu x^\nu,d ## constant.

Homework Equations


I don't think these are very relevant because they're not the transformations for the question but
$$\Delta x = \gamma(\Delta x' + v\Delta t')$$
$$\Delta t = \gamma(\Delta t' + v\Delta x'/c^2)$$
$$\Delta x' = \gamma(\Delta x - v\Delta t)$$
$$\Delta t' = \gamma(\Delta t - v\Delta x/c^2)$$

The Attempt at a Solution


I wrote the ## S' ## coordinates out and using ## x'^0=t'##,##x'^1=x'##,##x'^2=y'##,##x'^3=z' ##, try to calculate the velocities but I don't think it's right. I'm not sure how to show a transformation preserves the particle velocity. Could anyone point me how to show this for the Lorentz transformations, and then I could try to do it for my transformations?
 
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Oh, and for inline math we use ## \#\# ## to start and end, not ##$##
 
BvU said:
Oh, and for inline math we use ## \#\# ## to start and end, not ##$##
I've fixed that now, thanks. Did you have something typed before "Oh,"?
 
Ummm, no ... :frown:
 
SevenHells said:
I have a particle moving with uniform velocity in a frame ##S##, with coordinates $$ x^\mu , \mu=0,1,2,3. $$
I need to show that the particle also has uniform velocity in a frame ## S' ##, given by
$$x'^\mu=\dfrac{A_\nu^\mu x^\nu + b^\mu}{c_\nu x^\nu + d}, $$
with ## A_\nu^\mu,b^\mu,c_\nu x^\nu,d ## constant.
"Uniform velocity" means zero acceleration. So you must show that if $$\frac{dv^i}{dt} \equiv \frac{d^2 x^i}{dt^2} = 0$$then
$$\frac{dv'^i}{dt'} \equiv\frac{d^2 x'^i}{dt'^2} = 0$$ (where ##i=1,2,3##).

BTW, what is the context of this problem? It's actually a classic -- the fractional linear transformations are known to be the most general transformations which preserve inertial motion. :-)

Not sure how much of a hint I should give you, so I'll start with this:

Work with the differentials, i.e., find ##dx^i## and ##dt## separately, then take their quotient to find an expression for ##v##. Take differential ##dv## similarly, and take its quotient with ##dt## to find the acceleration.

Further hints: use the chain rule to compute the various differentials.
 
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