I should clarify:
Part A requires 16hp (23.34lb.ft.) @ 3600 Rpm.
16HP * 5252 / 3600 = 23.34222 lb.ft.
The calculations on Part B were using 1/4HP @ 450 RPM, 8:1 G.R.
Meaning:
.25 * 5252 / 450 = 2.91777lb.ft.
At an 8:1 G.R., that would mean 2.917 * 8 = 23.336lb.ft.
450 RPM * 8 = 3600 RPM...
Here is some basic information:
Part A requires 23.34lb.ft. (31.644 Nm) of torque @ 3600 RPM to function.
Part B is a slave motor, 12VDC(or BLDC).
This inquiry is specifically directed at Part B:
Is it possible to achieve the target required torque rating using Part B?
I have calculated 1/4...