Recent content by Shahab Mirza

  1. Shahab Mirza

    Velocity Related Problem -- A body is thrown upward....

    It means that I should apply time equation of projectile . It will be correct option ?
  2. Shahab Mirza

    Velocity Related Problem -- A body is thrown upward....

    Vf is velocity at max height where ball stops for a while
  3. Shahab Mirza

    Projectile Problem: Horizontal Velocity Analysis

    ops sorry , it is VX versus time , yes now explain how graph is horizontal line ?
  4. Shahab Mirza

    Velocity Related Problem -- A body is thrown upward....

    Thanks a lot sir . Oh so it means that T =10 seconds was the time ball was in air it means that it was time taken from throwing ball upward and then catching it in hand hence where the ball momentarily stops , the time till then is 5 seconds . It means I didn't understood question correctly...
  5. Shahab Mirza

    Projectile Problem: Horizontal Velocity Analysis

    The following graph (ATTACHED) represents the horizontal velocity component (Vx) verses time for a projectile thrown horizontally off a cliff. (Ignored Air resistance) . But I thought that graph will be a 45 degree slope straight line , because Horizontal component of velocity of projectile...
  6. Shahab Mirza

    Motion Problem Constant Acceleration from 10 to 50 m/s in 2 secs

    Yes I understood Sir , Thanks , I will keep all these things in my knowledge . Thanks
  7. Shahab Mirza

    Motion Problem Constant Acceleration from 10 to 50 m/s in 2 secs

    Its very kind of you , Thanks for sharing knowledge , actually I am going to give medical college admission test this year , it has 3 subjects on which test will be based , 1 BIology . 2 Physics 3 Chemistry . so these little concepts will help me a lot , Thanks
  8. Shahab Mirza

    Motion Problem Constant Acceleration from 10 to 50 m/s in 2 secs

    Thanks , but the sir who replied above gave this solution. Here u(initial velocity)=10m/s, v(final velocity)=50m/s, a=constant (so apply equations as it is a 1D problem), s=60, t=? Using eq. 2 we get 2500-100=2*a*60 a=20m/s*s Now using this value of 'a' in eq 1 we get; 50=10+20*t t=2sI think...
  9. Shahab Mirza

    Motion Problem Constant Acceleration from 10 to 50 m/s in 2 secs

    Yes Thanks , this was really a perfect solution , I was wondering how s = vt going to solve this , Thanks alot
  10. Shahab Mirza

    Motion Problem Constant Acceleration from 10 to 50 m/s in 2 secs

    Thanks , But I am not satisfied with my solution, u know why sir? because S = vt is possible when initial velocity is 0 means herz equation s = vit + 1/2 a t^2 , but this eq can only be reduced to s =vt when acceleration is unity and initial velocity is 0 , in my case it isn't ? please make me...
  11. Shahab Mirza

    Velocity Related Problem -- A body is thrown upward....

    Homework Statement A body is thrown upward and remains in air for 10 seconds , the initial velocity at which it was thrown in is? The Attempt at a Solution g = -10 , t = 10 s , vf = 0 , vi = ? Vf = vi + gt 0=vi + (-10) (10) Vi = 100 but its answer is not 100 its answer is 50 help me please...
  12. Shahab Mirza

    Motion Problem Constant Acceleration from 10 to 50 m/s in 2 secs

    Homework Statement A car traveling with constant acceleration increases its speed from 10 m/s to 50 m/s over a distance of 60 m . how long does this take? a. 2 seconds b. 4 seconds . The Attempt at a Solution Data : Avg Velocity = 10 + 50 / 2 = 30m/s Distance = 60 meter time = ? Solution ...
  13. Shahab Mirza

    How to solve this Cosine Law Equation?

    Sorry for late reply sir , actually internet was down since days . Yes this looks way better and way easy too because we have atleast 20 chapters of Physics with too much number of articles , so we have to find such a way that keeps thing in our mind for long term and save time , Thanks
  14. Shahab Mirza

    How to solve this Cosine Law Equation?

    ops sorry by angle I mean Triangle diagram or something like that wasn't mentioned in the question Sir . Yes exactly this is the answer you are right . I also have an quick alternate to solve this question I found this method more quicker and applicable to variety of questions . See below I...
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